V = 4/3 * 3.14 * 9^3 = 3052.08
Answer is B
Answer: q³⁰
Explanation:
First just solve the first part using the exponent rules
p²q⁵ becomes 1/p-⁸q-²⁰ then we flip the fraction so the exponents become positive. Now we have p⁸q²⁰.
Before multiplying the other equation, we must simplify. p-⁴q⁵ becomes 1/p⁴q-⁵ and since it's the exponents being raised to a power we simply multiply the inner exponents times the outer exponent which yields 1/p⁸q-¹⁰. We must make q-¹⁰ positive so we will then bring it to the numerator of the fraction which gives us: q¹⁰/p⁸.
Multiply q¹⁰/p⁸ * p⁸q²⁰/1 = p⁸q³⁰/p⁸ divide the p exponents by each other which yields 0 since when u divide exponents you just subtract them so 8 - 8 = 0. Your answer is now q³⁰/1 or just q³⁰
Answer:
32
Step-by-step explanation:
The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...
18 -10 = 8 . . . . . take only algebra i
So the number taking any kind of algebra is ...
20 + 8 = 28
and the number not taking either subject is ...
60 -28 = 32 . . . not taking either subject
Answer:
LSA = 532 yds ^2
Step-by-step explanation:
We do not add the triangles in because they are the bases and the bases do not get added in the lateral surface areas.
From left to right
Rectangle 1
A = lw = 9.9 *20 =198
Rectangle 2
A = lw = 6.8 *20 =136
Rectangle 3
A = lw = 9.9 *20 =198
Add them together
198+136+198
532
LSA = 532 yds ^2
Answer:
Equivalent systems of equations review
Step-by-step explanation:
We're given two systems of equations and asked if they're equivalent.
x + 4y = 8 (1)
4x + y = 2 (2)
Interestingly, if we sum the equations in System A, we get:
Replacing the first equation in System A with this new equation, we get a system that's equivalent to System A:
This is System B, which means that System A is equivalent to System B.
