All categories

2 years ago

Plzzzzzzzzzz helpppppppp

Mathematics

1 answer:

Minchanka [31]2 years ago

7 0

Answer:

i'd say do it with division what equals 31? im not going to say the staright up answer

]

You might be interested in

The circle below has center H. Suppose that =m∠FHG64°. Find the following.

Tatiana [17]

Answer:

(a) m FG = 64°

(b) m ∠FEG = 32°

Step-by-step explanation:

m∠FHG64° = m FG = 64°

m ∠FEG = 32° is half of m∠FHG64°

6 0

3 years ago

A jewelry shop is having a sale. A bracelet is now reduced to £420. This is 70% of the original price. Work out the of the ring

Tamiku [17]

420÷70%
=£600
the original price of the ring is £600

6 0

3 years ago

Zoey needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer for 3

solmaris [256]

X = Amount paid one hour
205.25 - 59 = 146.25
3.25x = 146.25
x = 146.25 ÷ 3.25

x= 45

6 0

2 years ago

Can someone plz help me with this one problem!!!!

Anarel [89]

Answer:

its 63..................

5 0

3 years ago

Read 2 more answers

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers