PLZ, I need help with this problem!

What makes apparent magnitude different from absolute brightness? Give an example in your response.

Lapatulllka [165]

Apparent magnitude isn’t the actual brightness, it’s what the brightness appears to be from earth, absolute brightness is the actual brightness an example is our sun it appears bright on earth but in space it is so much more brighter

8 0

3 years ago

Suppose theta(????) measures the minimum angle between a clock’s minute and hour hands in radians. What is theta′(????) at 4 o’c

makvit [3.9K]

Answer:

$\frac{\pi }{30}$ radians per minute.

Step-by-step explanation:

In order to solve the problem you can use the fact that the angle in radians of a circumference is 2π rad.

The clock can be seen as a circumference divided in 12 equal pieces (because of the hour divisions). Each portion is $\frac{1}{12}$

So, you have to calculate the angle between each consecutive hour (Let ∅ represent it). It can be calculated dividing the angle of the entire circumference by 12.

∅= $\frac{2\pi }{12} = \frac{\pi }{6} rad$

Now, you have to find how many pieces of the circumference are between 12 and 4 to calculate the angle (Because 4 o'clock is when the minute hand is in 12 and the hour hand is in 4)

There are 4 portions from 12 to 4, so the angle (Let α represent it) is:

α= $(4)\frac{\pi }{6} = \frac{2\pi }{3}$