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2 years ago

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Mathematics

1 answer:

k0ka [10]2 years ago

4 0

Answer:

∠BAC=70°

Step-by-step explanation:

If AB || CD and BC II DE that means the two triangles are congruent or the same, this means ∠BAC°=∠DCE°, ∠ABC°=∠EDC°, and ∠BCA°=∠DEC°. The three angles of a triagle add up to 180°. If ∠DEC=45° and ∠EDC=65°

Total°-(∠DEZ°+∠EDC°)=∠DCE° or ∠ECD°

180°-(65°+45°)=70°

∠BAC°=∠DCE°

Therefore ∠BAC=70°

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In a class of 75 students, 50 of them are girls and 25 of them are boys. What percentage are girls?

klio [65]

Answer:

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Step-by-step explanation:

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2 years ago

What's something that could go wrong if you use numbers that are not precise?

Strike441 [17]

Answer:

There are a lot of things that can go wrong, especially when we have an error in a measure that we use a lot of times (each time, that error increases).

For example, you think that each meter of fence costs $5, but the actual price is $5.30, and you need 40 meters, then you think that you may need to pay:

40*$5 = $200

But they will actually charge you:

40*$5.30 = $212.

Now this is a small example, now let's go to medicine, suppose that you want to trait cancer with radiation in a pacient, if you do not use precise measures for the dosage of radiation or the measures of the tumor, you may cause a lot of damage in the patient. (And similar cases if you want to give some medication and the numbers that you use are not precise, you may overdose the patient)

So the use of precise numbers may be critical in a lot of scenarios.

6 0

3 years ago

he XO Group Inc. conducted a survey of brides and grooms married in the United States and found that the average cost of a weddi

ahrayia [7]

Answer:

A. P(X<20,000) = 0.0392

B. P(20,000 < x < 30,000) = 0.488

C. Amount = $39,070

Step-by-step explanation:

From XO group website

Cost of a wedding = $29,858

Mean, μ = $29,858

Standard Deviation, σ =$5,600

a. Calculating the probability that a wedding costs less than $20,000

P(X<20,000)?

First, the z value needs to be calculated.

z = (x - μ)/σ

x = 20,000

z = (20,000 - 29,858)/5600

z = -1.76

So, P(X<20,000) = P(Z<-1.76)

From the z table,

P(Z<-1.76) = 0.0392

P(X<20,000) = 0.0392

b. Calculating the probability that a wedding costs between $20,000 and $30,000

P(20,000 < x < 30,000)

First, the z value needs to be calculated.

z = (x - μ)/σ

When x = 20,000

z = (20,000 - 29,858)/5600

z = -1.76

When x = 30,000

z = (30,000 - 29,858)/5600

z = 0.02

P(20,000 < x < 30,000) = P(-1.76 < z <0.02) --- using the z table

P(-1.76 < z <0.02) = 0.508 - 0.0392

P(-1.76 < z <0.02) = 0.4688

P(20,000 < x < 30,000) = 0.488

c. Using the following formula, we'll get the amount it'll a wedding to be among the 5% most expensive

z = (x - μ)/σ where x = amount

Make x the subject of formula

x = σz + μ

Fist we need to get the z value of 5%

z0.05 = 1.645

x = σz + μ becomes

x = 5600 * 1.645 + 29,858

x = $39,070

Amount = $39,070

5 0

2 years ago

The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar

Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5%

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean debt ratio of Ohio banks = 6%

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 1.83%

n = sample of banks = 7

So, test statistics = $\frac{6-3.5}{\frac{1.83}{\sqrt{7} } }$ ~ $t_6$

= 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

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3 years ago

Let u = 14. What is the value of 4u?

77julia77 [94]

Answer: B 56

Step-by-step explanation:

3 0

3 years ago

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