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Dominik [7]
2 years ago
11

-

Mathematics
1 answer:
k0ka [10]2 years ago
4 0

Answer:

∠BAC=70°

Step-by-step explanation:

If AB || CD and BC II DE that means the two triangles are congruent or the same, this means ∠BAC°=∠DCE°, ∠ABC°=∠EDC°, and ∠BCA°=∠DEC°. The three angles of a triagle add up to 180°. If ∠DEC=45° and ∠EDC=65°

Total°-(∠DEZ°+∠EDC°)=∠DCE° or ∠ECD°

180°-(65°+45°)=70°

∠BAC°=∠DCE°

Therefore ∠BAC=70°

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Solve by elimination <br><br> -6x + 7y= 0<br> -2x + 3y=4
nignag [31]

Answer:

Its c

Step-by-step explanation:

7 0
3 years ago
What 2 numbers multiply to get 4.32 while also dividing to equal 3?
Alekssandra [29.7K]

Answer:

3.6 and 1.2

Or

-3.6 and -1.2

Step-by-step explanation:

Let x and y be the two numbers

xy = 4.32

x/y = 3

x = 3y

3y² = 4.32

y² = 1.44

y = +/- 1.2

x = +/- 3.6

6 0
3 years ago
The altitude of a triangle is 2 m longer than its base. What are the dimensions of the altitude and the base if thearea of the t
HACTEHA [7]

Step-by-step explanation:

Let base of triangle be x m.

Therefore, altitude =( x + 2)m

area \: of \:  \triangle =  \frac{1}{2}  \times base \times altitude \\  \\ 40 =  \frac{1}{2}  \times x \times (x + 2) \\  \\ 80 =  {x }^{2} +2x \\  \\   {x}^{2}  + 2x - 80 = 0 \\  {x}^{2}  + 10x - 8x - 80 \\ x(x + 10) - 8(x + 10)  = 0\\ (x + 10)(x - 8) = 0 \\ x + 10 = 0 \:  \: or \:  \: x - 8 = 0 \\ x =  - 10 \:  \: or \:  \: x = 8 \\ base \: can \: not \: be \:  - ve \\ x \neq - 10 \\ x = 8 \\ x + 2 = 8 + 2 = 10 \\

Therefore

Altitude = 10 m

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8 0
3 years ago
Please help me asap<br>​
Lera25 [3.4K]

Answer:

Step-by-step explanation:

From the picture attached,

∠4 = 45°, ∠5 = 135° and ∠10 = ∠11

Part A

∠1 = ∠4 = 45°  [Vertically opposite angles]

∠1 + ∠3 = 180° [Linear pair of angles]

∠3 = 180° - ∠1

     = 180° - 45°

     = 135°

∠2 = ∠3 = 135°  [Vertically opposite angles]

∠8 = ∠5 = 135° [Vertically opposite angles]

∠5 + ∠6 = 180° [Linear pair of angles]

∠6 = 180° - 135°

∠6 = 45°

∠7 = ∠6 = 45° [Vertically opposite angles]

By triangle sum theorem,

m∠4 + m∠7 + m∠10 = 180°

45° + 45° + m∠10 = 180°

m∠10 = 180° - 90°

m∠10 = 90°

m∠10 = m∠12 = 90°  [Vertically opposite angles]

m∠10 = m∠11 = 90° [Given]

Part B

1). ∠1 ≅ ∠4  [Vertically opposite angles]

2). ∠7 + ∠5 = 180° [Linear pair]

3). ∠9 + ∠10 = 180° [Linear pair]

7 0
3 years ago
Whats the Quotient for 95÷5
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Answer:

12

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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