Answer:
The sum is a binomial of degree 3.
Step-by-step explanation:
You are adding two binomials. Each binomial has two terms.
The terms 6s^2t and 4s^2t are like terms and combine to give the sum 10s^2t.
The terms -2st^2 and -3st^2 are like terms and combine to give the sum -5st^2.
The sum of the binomials is the binomial 10s^2t - 5st^2.
Since each original binomial is of degree 3, the sum is also of degree 3.
Answer: The sum is a binomial of degree 3.
We have to do BIMDAS
so starting with the brackets we do
35+27
which is 62
62÷4×12
then we work left to right for multiplication and division
62÷4
which is 15.5
then we finish with 15.5×12
which is 186
hope it helps.
<span>It costs $7.00 to play a straightforward game in which a dealer gives you one card from a deck of 52 cards. </span><span>
</span><span>
If the card is a heart, spade, or diamond, you lose. </span><span>
</span><span>
If the card is a club other than the queen of clubs, you win $11.50. </span><span>
</span><span>
If the card is the queen of clubs, you win $50.00. </span><span>
</span><span>
The random variable x represents your net gain from playing this game once, or your winnings minus the cost to play. What is the mean of x, rounded to the nearest penny?</span><span>
</span><span>
------
Random "winnings"::.....-7.......4.50......43</span><span>
</span><span>
Probabilities::........ 39/52....12/52....1/52 </span><span>
</span><span>
------------------------------------------------------</span><span>
</span><span>
u(x) = [39*-7 + 12*4.5 + 43]/52 = -$3.38
</span>
The answers are complex numbers...
Here's why...
---------
p+q=18
pq=82
---------
Therefore:
p=18-q
p=82/q
------------
Therefore:
18-q=82/q
q(18-q)=q(82/q)
18q-q²=82
(-1)(18q-q²)=82(-1)
q²-18q=-82
(q-9)²-9²=-82
(q-9)²-81=-82
(q-9)²=-82+81
(q-9)²=-1
q-9=-√(-1)=-i
q-9=√(-1)=i
-----------
Therefore:
q=9-i
q=9+i
-------------
ANSWERS:
When q=9-i, p=9+i
When q=9+i, p=9-i
-----------
Proof:
p+(9-i)=18
p+9-i=18
p=18-9+i
p=9+i
....
p+(9+i)=18
p+9+i=18
p=18-9-i
p=9-i
--------------
More proofs:
p=82/(9+i)
p=(82/(9+i))*((9-i)/(9-i))
p=(82(9-i))/(81-9i+9i-i²)
p=(82(9-i))/(81-(-1))
p=(82(9-i))/82
p=9-i
---------------
p=82/(9-i)
p=(82/(9-i))*((9+i)/(9+i))
p=(82(9+i))/(81+9i-9i-i²)
p=(82(9+i))/(81-(-1))
p=(82(9+i))/82
p=9+i
