Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
3(5)+15= 30
because BIDMAS so we would multiply 3 by 5 then add the answer which would be 15 to 15 and we would get 30.
The correct answer is
9x^2/10y^3
Answer:
a
Step-by-step explanation:
hope this helps
;)
Answer:
89,000 I think
Step-by-step explanation:
just subtract 125,000 by 36,000
although Its a guess
