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3 years ago

13

Please help

1 answer:

frosja888 [35]3 years ago

4 0

Answer:

1/3

Step-by-step explanation:

i found it easily also im good with slopes :)

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If Judy completes a puzzle by herself, it takes her 3 hours. Working with Sal, it only takes them 2 hours.What is the missing va

aliina [53]

Answer:

It means the Judy's rate to complete the puzzle is $\frac{1}{3}.$

Step-by-step explanation:

If Judy completes a puzzle by herself, it takes her 3 hours.

Working with Sal, it only takes them 2 hours

We have been given the rates of time taken by Judy and Sal to complete a puzzle.

We can see from our given table that Sal's rate is r. We are told that Judy completes a puzzle by herself, it takes her 3 hours. working with Sal, it only takes them 2 hours.

It is given that Judy completes a puzzle by herself, it takes her 3 hours.

so part of puzzle completed by Judy in one hour would be $\frac{1}{3}$

Therefore, the part of puzzle completed by Judy in one hour is $\frac{1}{3}.$

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3 years ago

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quester [9]

The answer would be (2,-2)

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3 years ago

How to find the domain in a table chart ?

Olin [163]

In a table, like the one below, the domain is usually listed in the left column and the range is listed in the right column. You can also refer to the domain as the input values, x, and the range as the output values, y, in a relation or function.

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2 years ago

Which expression is equal to x + (f + g)?

vlabodo [156]

X + (f + g) = <span>(x + f) + g

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3 years ago

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Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

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3 years ago