Explain the difference between an i/o‐bound process and a cpu‐bound process.

1 answer:

7 0

An I/O bound process can't finish because it's waiting for I/O (which is provided by the OS). A CPU bound process can't finish because it can't get scheduled in the processor enough.

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You want to find the distance between two points.

maks197457 [2]

Answer:

For the first picture, choose the second pair, and for the second one, choose the first pair

Explanation:

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2 years ago

Match the different sources of payments to their descriptions. an electronic device that aids consumers to make online payments

LekaFEV [45]

Automatic Draft- A convenient payment method where funds are automatically debited from your account.

Cash- The physical form of currency.

Credit Card- Allows you to make a purchase and pay for it later.

Digital Wallet- An electronic device that aids consumers to make online payments through various websites.

For anyone still looking, hope this helps.

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2 years ago

Extension: Cash Register Program

Evgesh-ka [11]

Answer:

hee hee 4 you are correct

Explanation:

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2 years ago

Again, suppose that n and r denote integer values where r > 0 and n ≥ 0. What are two "simple" values, say lowEnough and tooH

enyata [817]

Answer:

Answer explained

Explanation:

From the previous question we know that while searching for n^(1/r) we don't have to look for guesses less than 0 and greater than n. Because for less than 0 it will be an imaginary number and for rth root of a non negative number can never be greater than itself. Hence lowEnough = 0 and tooHigh = n.

we need to find 5th root of 47226. The computation of root is costlier than computing power of a number. Therefore, we will look for a number whose 5th power is 47226. lowEnough = 0 and tooHigh = 47226 + 1. Question that should be asked on each step would be "Is 5th power of number < 47227?" we will stop when we find a number whose 5th power is 47226.

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2 years ago

A common use-case for dictionaries is to store word counts. Let's modify our program below to store the count for each unique wo

baherus [9]

Answer:

word_count={}

for i in text.split:

if i in word_count:

word_count[i]+=1

else:

word_count[i]=1

print word_count

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2 years ago