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Readme [11.4K]
2 years ago
11

For what value of x is sin(x) = cos(32°), where 0°< x < 90°?

Mathematics
1 answer:
sergiy2304 [10]2 years ago
3 0

Answer:

B

Step-by-step explanation:

Use the cofunction identies that states that

\sin(90 - x)  =  \cos(x)

\sin((90 - x))  =  \cos(32)

\sin(90 - 32)  =  \cos(32)

\sin(58)  =  \cos(32)

B is the answer.

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