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Anettt [7]
2 years ago
14

What is x?

Mathematics
2 answers:
marta [7]2 years ago
7 0

Answer:

x= \frac{1}{4\\}

Step-by-step explanation:

-3÷ -12 = 0.25

0.25 as a fraction is \frac{1}{4}

mrs_skeptik [129]2 years ago
4 0

Answer:

x = 1/4

Step-by-step explanation:

−12x=−3 (Given)

x = 0.25 (Divide) (value became positive because negative was divided by negative).

0.25 in fraction = 1/4

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PLS HELP NEW THIS QUICK!!!
vivado [14]

Answer:

Option C

Step-by-step explanation:

3\frac{1}{5} \times 2\frac{1}{5}

Lets convert it into improper fraction.

\frac{16}{5} \times \frac{11}{5} = \frac{16 \times 11}{5 \times 5} = \frac{176}{25}

Lets convert \frac{176}{25} into a mixed fraction.

=> \frac{176}{25} = 7\frac{1}{25} = 7.04

Rounding off 7.04 gives 7 and rounding 7 further gives 10.

So , the estimate of the product is 10

7 0
3 years ago
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Which algebraic expression is a polynomial with a degree of 3? 4x3 –  2y3 + 5y2 – 5y 3y3 –  –xy
Svetllana [295]
Your answer should be B.
7 0
3 years ago
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In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
An equation in the system is y = x + 1. What is the other equation in the system if the solution is only at (0, 1)?
Setler [38]
<span>x + y = 0 hope this helps </span>
6 0
3 years ago
Q5.Jumbo is standing on top of a cliff looking at a speed boat out at sea.The vertical of the cliff from the base (sea level) to
Leni [432]

Answer:

A) 150 m

B) 180.28 m

Step-by-step explanation:

A) In order to find the horizontal distance from the base of the cliff to the speed boat, use the Pythagorean theorem to calculate the length of the missing side.

We are told that one of the sides is 80 m and the hypotenuse is 170 m. Therefore,

  • a² + b² = c²
  • (80)² + b² = (170)²
  • b² = 170² - 80²
  • b² = 22500
  • b = 150

The horizontal distance between the base of the cliff and the boat is 150 m.

B) Now, the side that was 80 m is now 100 m (includes the height that the helicopter is above Jumbo). The horizontal distance remains the same, 150 m, but the hypotenuse is different. Solving for the hypotenuse will give us the distance between the helicopter and the speed boat.

  • (100)² + (150)² = c²
  • 32500 = c²
  • 180.28 = c

The distance between the helicopter and the speed boat is 180.28 m.

8 0
3 years ago
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