All categories

2 years ago

I need help pls help

Mathematics

2 answers:

tia_tia [17]2 years ago

7 0

Answer:

here is the answer bro its right

16y+7z

Step-by-step explanation:

yKpoI14uk [10]2 years ago

7 0

Answer:

it's 16y + 7z

Step-by-step explanation:

I positive that this is right

You might be interested in

Is this a function?......

ss7ja [257]

Answer:

yes it is a polynomial function

4 0

2 years ago

Read 2 more answers

What is the answer to the following equations

rosijanka [135]

I think 1njbewbvdn bhv hgf

6 0

2 years ago

What is the equation of this line?

Oduvanchick [21]

Answer:

y=4/3x-3

Step-by-step explanation:

+4x-(-3y)=1-1/3

5 0

2 years ago

16+ n/4 =22 <br><br> Help me solve please and thank you :))

Luden [163]

Answer:

n = 24

Step-by-step explanation:

16+ n/4 =22

Subtract 16 from each side

16-16+ n/4 =22-16

n/4 = 6

Multiply each side by 4

n/4*4 = 6*4

n = 24

4 0

3 years ago

2 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

Ivanshal [37]

Answer:

This series is divergent

Step-by-step explanation:

we are given a series

Firstly, we will find nth term

Numerator:

3, 4, 5,...

so, nth term will be

$a_n=n+3$

Denominator:

4,5,6,....

so, nth term will be

$b_n=n+4$

so, we can find it's nth term as

$c_n=\frac{n+3}{n+4}$

we can use divergent test

$\lim_{n \to \infty} c_n=\lim_{n \to \infty} \frac{n+3}{n+4}$

we can divide top and bottom by n

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}$

$\lim_{n \to \infty} c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}$

now, we can plug n=inf

$\lim_{n \to \infty} c_n= \frac{1+0}{1+0}$

$\lim_{n \to \infty} c_n=1$

Since, it is non-zero value

so, this series is divergent

8 0

3 years ago

I need help pls help​

I need help pls help