Answer:
$21
Step-by-step explanation:
Provided total value = $50
$50 = 5,000 cents.
We are provided,
10 cent coins value = 30% of total value
= 0.3
5,000 cents = 1,500 cents
Value of 20 cents coin = 28% of total value
= 0.28
5,000 cents = 1,400 cents
Therefore, remaining value of cents = Total value of 50 cents coins
5,000 cents - value of 10-cent coins - value of 20-cent coins = total value of 50 cents coins
5,000 - 1,500 - 1,400 = 2,100 cents = $21
Which means number of 50 cents coin = 
Alternatively,
To calculate value of 50 cent coins
Total value = 100%
Value in 10-cent coins + 20-cent coins = 30% + 28% = 58%
Value in 50-cent coins = 100 - 58 = 42%
= $50
42% = $21
The LCM of 4,10 and 12 is 60.
Answer:
Step-by-step explanation:
(-2,2) ...x1 = -2 and y1 = 2
(4,6)..x2 = 4 and y2 = 6
midpoint formula :
m = ((x1 + x2) / 2 , (y1 + y2) / 2)
m = ((-2 + 4) / 2 , (2 + 6) / 2)
m = 2/2 , 8/2
m = (1,4) <===
Answer:
30.18
Step-by-step explanation:
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.