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3 years ago

Which property of multiplication is shown? 9 × 0 − 6 × 0 = (9 − 6) × 0

Mathematics

2 answers:

Pavel [41]3 years ago

8 0

Answer:

Distributive property of multiplication

Step-by-step explanation:

JulsSmile [24]3 years ago

7 0

Answer: Associative property

Step-by-step explanation: it is the same equation but they switched the numbers around on the other side of the equal sign so therefore its associative property

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-2x + 3x - 5 = 6 - 21 FIND x

trasher [3.6K]

Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

5 0

3 years ago

Which ordered pairs are solutions to the inequality y−4x≤−6 ?

amid [387]

I think it is A, (-2,-14)

7 0

3 years ago

Jamie bought 5/8 of wheat flour. He also bought 1/4 pound of white flour. How much flour did he buy

KonstantinChe [14]

7/8 you have to make 1/4 into 2/8 and 2/8+5/8=7/8

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4 years ago

Read 2 more answers

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

3 years ago

What is the greatest common factor of the polynomial -25y^3+15y^2-5y

Sonbull [250]

Answer:

-5y

Step-by-step explanation:

4 0

3 years ago