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2 years ago

10 cm А B 7 cm 19 cm D С 15 cm Calculate the area of ABCD.

Mathematics

2 answers:

IgorLugansk [536]2 years ago

5 0

Answer:

the area is 150 cm^2

Step-by-step explanation:

Hope this helps

Dmitriy789 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

Ratio+Yb better

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Caroline puts $400 into a savings account that earns 6% annually. Write a function that represents this situation, where t is th

DaniilM [7]

Answer: 19 years

Step-by-step explanation:

Given

Amount invested $\$400$

Rate of interest $R=6\%$

after 1-year amount becomes

$A=400\left (1+6\%\right)\\A=400\left (1+0.06\right)\\A=400\times 1.06\\A=\$424$

After n years it is

$A=400\left (1.06\right)^n$

Sum accumulated is $\$1200$

$\Rightarrow 1200=400\left(1.06\right)^n\\\Rightarrow 3=\left(1.06\right)^n\\\text{Taking log both sides}\\\Rightarrow n=\dfrac{\ln 3}{\ln 1.06}\\\\\Rightarrow n=18.85\approx 19\ \text{years}$

5 0

2 years ago

Please help me!!! :(

PSYCHO15rus [73]

Answer:

$15.75x^{10}y^{19}$

Step-by-step explanation:

To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.

After applying the binomial theorem and simplifying, you should get:

$512x^{18}y^{27}-576x^{16}y^{25}+288x^{14}y^{23}-84x^{12}y^{21}+\frac{63x^{10}y^{19}}{4}-\frac{63x^8y^{17}}{32}+\frac{21x^6y^{15}}{128}-\frac{9x^4y^{13}}{1024}+\frac{9x^2y^{11}}{32768}-\frac{y^9}{262144}$

Our 5th term here is: $\frac{63x^{10}y^{19}}{4}$ which is equal to $15.75x^{10}y^{19}$

~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~

4 0

2 years ago

Can any negative integer be greater than a positive integer explain

Keith_Richards [23]

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

$y < 0 < x$