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Len [333]
3 years ago
6

Determine the zeros of the function f(x) = 3x^2 -7x+1

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0
I will use the quadratic formula.

\text{The zeros of function:}\ f(x)=0\\\\f(x)=3x^2-7\\\\f(x)=0\to3x^2-7x+1=0\\\\a=3;\ b=-7;\ c=1\\\\b^2-4ac=(-7)^2-4\cdot3\cdot1=49-12=37\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-(-7)-\sqrt{37}}{2\cdot3}=\dfrac{7-\sqrt{37}}{6}\\\\x_2=\dfrac{-(-7)+\sqrt{37}}{2\cdot3}=\dfrac{7+\sqrt{37}}{6}

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In the diagram, VW = 3, WX = 4, and VX = 8. Is line WX tangent to point V?
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How you round 348 to the nearest ten and to the nearest hundred explain
givi [52]

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Nearest ten-350

Nearest hundred-300

Step-by-step explanation:

#When rounding to the nearest ten, we look at the ones digits in a number:

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Given the number 348, 8 in the ones digit greater than 4 so we round to the next ten:

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#When rounding to the nearest hundred, we look at the tens digits in a number:

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Given the number 348, 4 in the tens digit less than 5 so we round down to the previous hundred:

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Using the rules of exponents

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7^{-2} = \frac{1}{7^{2} } = \frac{1}{49} → C

5 0
4 years ago
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