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3 years ago

What is the Sum of 5 times z and 4 divided by two is 7

2 answers:

8 0

What is the Sum of 5 times z and 4 divided by two is 7
would look like this

5x+4÷2=7 now lets solve

first you simplify both sides of the equation it'll look like this

5x+2=7

Now subtract 2 from both side, itll look like this:

5x+2-2=7-2=5x=5

Now we divide both sides by 5 itll look like this

5x/5=5/5 so 5x/5 will get crossed out and 5/5 is ONE

Answer is x=1

8_murik_8 [283]3 years ago

3 0

Sum of 5 times z and 4 divided by two is 7.

$\frac{5z+4}{2} = 7$

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The circle below has center C, and its radius is 5 in. Given that m

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3 years ago

A plane descended 922.02 meters in 5.5 minutes. What is the plane's rate of descent?

UkoKoshka [18]

The rate of descent is 164.64 meters / minute

To get this answer you just divide the total number of meters descended by the total number of minutes passed.

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7 0

3 years ago

(07.05 HC)

lianna [129]

Answer:

Step-by-step explanation:

2×8=16

not 10 that is why c is correct

8 0

3 years ago

(5x^3-8x^2+9x+12)/(x-3) please answer with sentences on how to do it step by step. thanks!

Anastaziya [24]

Answer:

$5x^2+7x+30+\frac{102}{x-3}$

Step-by-step explanation:

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\$

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}$

6 0

3 years ago

Read 2 more answers

Find the Area of the figure below, composed of a parallelogram and two semicircles. Round to the nearest tenths place.

svet-max [94.6K]

Answer:

100.3 units²

Step-by-step explanation:

✅Find the area of the parallelogram:

Area of Parallelogram is given as base × height

base = 10

height = 5

Area of Parallelogram = 10*5 = 50

✅Next, find the area of the two semicircles:

The two semicircles = 1 circle

Area of circle = πr²

r = 8/2 = 4

Area = π*4² = 16π = 50.3 (nearest tenth)

✅Area of figure = 50 + 50.3 = 100.3 units²

3 0

3 years ago