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torisob [31]
4 years ago
7

Question in attachment

Mathematics
1 answer:
Elan Coil [88]4 years ago
7 0

Answer:

The range within 1 standard deviation :155.12 ,328.38

Step-by-step explanation:

Data: 338+160+210+180+166+272+128+409+240+250+160+300+340+200+194+132+202+180+420+380+325+185+233+198

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}

Mean =\frac{338+160+210+180+166+272+.........+233+198}{24}

Mean =241.75

\text{Standard deviation} = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Standard deviation = \sqrt{\frac{(338-241.75)^{2}+(160-241.75)^{2}+......+(185-241.75)^{2}+(233-241.75)^{2}+(198-241.75)^{2}}{24-1}}

Standard deviation =86.63

Range within 1 standard deviation :(\mu-\sigma,\mu+\sigma)

Range within 1 standard deviation :(241.75-86.63,241.75+86.63)

Range within 1 standard deviation :155.12 ,328.38

Hence The range within 1 standard deviation :155.12 ,328.38

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natka813 [3]

Answer: x² + y² = 25

Step-by-step explanation: As we have x²+y²=25 (A) as options,

                                                                x-y=1 (B)

                                                                x+y=25 (C)

                                                                x²+y²=5 (D)

We can rule out B and C as they are not circles. Circles must be

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As the circle must pass through (3,4), we can substitute as x=3 and y=4

(A) 3² + 4² = 9 + 16 = 25 ok

(D) 3² + 4² = 9 + 16 = 25 ≠ 5

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4 0
3 years ago
How do I start This?
pav-90 [236]
\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{unit}{cost}&\stackrel{total}{value}\\
&------&------&------\\
Raisins&11&2.30&25.3\\
Peanuts&p&4.50&4.5p\\
------&------&------&------\\
mixture&m&3.29&3.29m
\end{array}

we know that, the mixture amount is the sum of 11 + p, or 11 + p = m.

we also know that, the total value is also a sum of 25.3 + 4.5p = 3.29m.

\bf \begin{cases}
11+p=\boxed{m}\\
25.3+4.5p=3.29m\\
----------\\
25.3+4.5p=3.29\left( \boxed{11+p} \right)
\end{cases}
\\\\\\
25.3+4.5p=36.19+3.29p\implies 1.21p=10.89\implies p=\cfrac{10.89}{1.21}
\\\\\\
p=\stackrel{lbs}{9}
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3 years ago
Fourteen more than the product of three and nine
Olegator [25]

Answer:

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Step-by-step explanation:

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