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2 years ago

PLS HELP 50 points

Mathematics

1 answer:

snow_tiger [21]2 years ago

8 0

Remember that there is 100 centimeters in a meter, and 1000 meters in a kilometer. If you multiply both values together (so you have a conversion of centimeters to kilometers) you get 100,000. Therefore, 100,000 centimeters makes a kilometer. Divide 320,000 by 100,000 and you get 3.2. Therefore, a centimeter would represent 3.2 kilometers.

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Need help with this NOW plzzzzz!!!!

Mazyrski [523]

Hello!

The circumference is the diameter multiplied by pi, or the distance around a circle. Since we already have the circumference, and need to find the diameter, we will divide the circumference by pi(3.14).

113.04/3.14=36

The diameter of the circle is 36 units.

I hope this helps!

3 0

3 years ago

If f(x)=3x^2-2x+1 find f(-2)

SIZIF [17.4K]

Answer:

Step-by-step explanation:

3(-2)^2 - 2(-2) + 1

12 - 2(-2) + 1

12 + 5

8 0

2 years ago

Read 2 more answers

An executive in an engineering firm earns a monthly salary plus bonus of 5700 dollars. If she earns a total of 91400 dollars per

Ray Of Light [21]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equation:

$12S + 5700 = 91400$

where $S$ is the monthly salary. Solving for $S$ will give us the answer:

$12S = 85700$

$S = 7141.67$

6 0

3 years ago

PLEASE HELPPPPP PLEASREER

sukhopar [10]

Answer:

its a :)

Step-by-step explanation:

hmu if you need an explanation or more help :)

5 0

3 years ago

The point P=\left(-\frac{1}{2},\,\, y\right)P=(− 2 1 ,y) lies on the unit circle shown below. What is the value of yy in simpl

sukhopar [10]

Answer:

$y = \frac{\sqrt{3}}{2}} \\\\$

Step-by-step explanation:

We are given a point P which lies on a unit circle

P = (-½, y)

Where x coordinate is -½ and y coordinate is y.

We are asked to find the value of y in simplest form.

Recall that a unit circle has a radius of 1 and is centered at the origin that is (0,0).

The equation of the unit circle is given by

$x^{2} + y^{2} = 1$

Since the point P lies on a unit circle, we can substitute this point into the equation of unit circle and get the value of y.

Substitute x = -½ and y = y

$(-\frac{1}{2} )^{2} + y^{2} = 1\\\\(\frac{1}{4} ) + y^{2} = 1\\\\y^{2} = 1 - \frac{1}{4} \\\\y^{2} = \frac{3}{4} \\\\y = \pm \sqrt{\frac{3}{4}} \\\\y = \pm \frac{\sqrt{3}}{2}} \\\\$

Assuming that the given point P lies in the 2nd quadrant, the value of y will be positive.

$y = \frac{\sqrt{3}}{2}} \\\\$

Therefore, the coordinates of the point P are

$P =( -\frac{1}{2} , \frac{\sqrt{3}}{2}}) \\\\$

6 0

3 years ago

PLS HELP *50 points*

PLS HELP 50 points