4tan^(2)x-((4)/(cotx))+sinxcscx
Multiply -1 by the (4)/(cotx) inside the parentheses.
4tan^(2)x-(4)/(cotx)+sinxcscx
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin...
Complete the multiplication to produce a denominator of cotx in each expression.
(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot...
Combine the numerators of all expressions that have common denominators.
<span>
(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
Answer:
The measure of angle DPA is 39°
Step-by-step explanation:
step 1
Find the value of x we know that arc AB+arc BC+arc CD+arc DA=360°
substitute the values
(5x+10)°+(x+1)°+3x°+(3x+25)°=360°
Solve for x
(12x+36)°=360°
12x=360°-36°
x=324°/12=27°
step 2 Find the measure of angle DPA
we know that The measurement of the external angle is the semi-difference of the arcs which comprises
m∠DPA=(1/2)[arc DA-arc BC]
arc DA=3(27)+25=106°
arc BC=27+1=28°
substitute the values
m∠DPA=(1/2)[106°-28°]=39°
Using translation concepts, considering the vertices (x,y) of figure p, the following rule is applied to find the vertices of figure r.
(x,y) -> (x + 4, y).
<h3>What is a translation?</h3>
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.
When a figure is shifted 4 units to the right, <u>4 is added to the x-coordinate</u>, hence, considering the vertices (x,y) of figure p, the following rule is applied to find the vertices of figure r.
(x,y) -> (x + 4, y).
More can be learned about translation concepts at brainly.com/question/28416763
#SPJ1
Answer:
B) The heights of the bear should equal the class frequency.
Step-by-step explanation:
In drawing a histogram, the heights of the bear should equal the class frequency. as in histogram height of bar represent the frequency density and it´s area represent the frequency of class interval. Frequency distribution are represented by mean of rectangle. Earlier in the bar graph, width of bar does not represent any information, however, histogram´s bar width represent class interval.
Answer:
It depends on how many dimes are in the piggy bank. It could be any answer that didn't have a 5 in the tenths place. For example, it couldn't be a number like $1.05 because any whole number multiplied by 10 would end in a 0