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Oduvanchick [21]
2 years ago
5

Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete

d the proof incorrectly? Explain.
CASHAPPING WHOEVER ANSWERS IN FULL DETAIL !!!! $10 ON ME!

Mathematics
1 answer:
Helga [31]2 years ago
6 0

Answer:

Becky, because her justification for the second statement should be "definition of supplementary angles" rather than "angle addition postulate."

Step-by-step explanation:

Becky completed the proof incorrectly because her justification for the second statement is not totally correct.

Angle addition postulate does not really apply here, as the sum of 2 angles may not give you exactly 180°.

However, the second statement, m<AKG + m<GKB = 180° and m<GKB + m<HKB = 180°, can be justified by the "Definition of Supplementary Angles".

The sum of supplementary angles = 180°.

Therefore, Becky completed the proof incorrectly.

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What is an algebraic expression for the area of the square picture and frame?
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Answer:

4

Step-by-step explanation:

because you have to multiple the number two

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2 years ago
A turtle population grows in a manner that closely resembles a geometric sequence. Given the table of values, determine the turt
AleksandrR [38]

The turtle population will be 486 after 5 years.

<u>Step-by-step explanation</u>:

The general form of a geometric progression or geometric sequence is a, ar, ar², ar³ and so on.

where,

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  • r = common ratio

<u>The formula to find the nth term in GP is :</u>

nth term = ar^{n-1}

The given sequence 6,18,54.

In this sequence,

  • The first term, a = 6
  • The common ratio, r = 18/6 = 3

5th term = 6\times3^{5-1}

⇒ 6\times3^{4}

⇒ 6\times81

⇒ 486

Therefore, after 5 years the population will be 486.

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3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

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1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

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3) \angle 1 \cong \angle 3 (vertical angles are congruent)

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7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

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