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➷ As there would be 2 circles, you'd need to find the area of a circle and then multiply it by 2
To start with, we can use this:
2 (
r^2)
^^ This represents the surface area of the two circles
A cylinder also has a rectangle which is rolled to form the shape
As we know, the formula of a rectangles area is length x width
The width of the rectangle would be equal to the circumference of a circle
circumference of circle = 
The length of the rectangle would be the height of the cylinder
We can use this:

This would calculate the surface area as it would find the area of the rectangle plus the area of the two circles.
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Answer:
Step-by-step explanation:
Since, both the triangles of the paperweight are congruent,
Their corresponding sides will be congruent.
3x + 2.5 = 4
3x = 4 - 2.5
x = 0.5
Similarly, 2y - 5 = 3x + y
2y - y = 3x + 5
y = 3x + 5
y = 3(0.5) + 5
y = 1.5 + 5
y = 6.5
Total length of the hypotenuse = 2y - 5
= 2(6.5) - 5
= 13 - 5
= 8
Option B is the answer.
Total length of the base = (3x + 2.5) + 4
= 3x + 6.5
= 3(0.5) + 6.5
= 8
Option B is the answer.
Step-by-step explanation:
<u>The standard form of linear equation:</u>
<u>Convert each equation into standard form:</u>
<h3>#5</h3>
- 3x = 18
- 3x + 0y - 18 = 0
- A = 3, B = 0, C = - 18
<h3>#6</h3>
- y/2 = - 5
- 0x + 1/2y + 5 = 0
- A = 0, B = 1/2, C = 5
The first answer is a function as it is the only one without repeating X values.
Answer:
A. 26.10 cm
B. 118.95 cm
Step-by-step explanation:
ST = 41^2 - 40^2 = c^2 = hypotenuse
ST = 1681 - 1600 = c^2
ST = c^2 = sq rt 681 =26.0959767014 = 26.1cm
Nearest 100th = 26.10
Length = 26.10 cm to nearest 100th
Perimeter of RSU we find (M) of SU first then add that to the other 3 lengths on the exterior of the triangle.
SU = 10^2 + 26.1^2 = c^2 = hypotenuse
SU = 100 + 681.21 = c^2
SU = c^2 = sqrt 781.21 = 27.9501341678 = 27.95cm
P TOTAL RSU = SU + TR + RS + TU
= 27.95 + 40+ 41 + 10 = 118.95cm