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3 years ago

Help me Plss Thank You ❤️

Mathematics

1 answer:

meriva3 years ago

3 0

Answer:

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1850=12 2918=20 5044 = ? 7573=56

wel

Answer:

1623 jajaggkcgaiahvs Kah kaye kaha

8 0

3 years ago

A professor of women's studies is interested in determining if stress affects the menstrual cycle. Ten women are randomly sample

BabaBlast [244]

Answer:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

$t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73$

$df=5+5-2=8$

$t_{crit}=\pm 2.306$

Reject H0: stress affects the menstrual cycle

Step-by-step explanation:

The statistic is given by the following formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2 \neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =2$ represent the sample size for group 2

Tha data given is:

Group 1 (High stress) : 20,23,18,19,22

Group 2 (Relatively stress free): 26,31,25,26,30

We can calculate the sample mean and the sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}$

$\bar X_1 =20.4$ represent the sample mean for the group 1

$\bar X_2 =27.6$ represent the sample mean for the group 2

$s_1=2.074$ represent the sample standard deviation for group 1

$s_2=2.702$ represent the sample standard deviation for group 2

And now we can calculate the statistic:

$t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73$

Now we can calculate the degrees of freedom given by:

$df=5+5-2=8$

Now we can calculate the critical value since the confidence is 95% the value for the significance would be $\alpha=1-0.95=0.05$ and the value for $\alpha/2 =0.025$ and if we find a critical value on th t distribution with 8 degrees of freedom that accumulates 0.025 of the area on each tail we got $t_{crit}=\pm 2.306$

Since our calculated value is lower than the critical value, we have enough evidence to reject the null hypothesis. And makes sense say that the difference between the two means are different at 5% of significance.

Reject H0: stress affects the menstrual cycle

5 0

3 years ago

The division property of equality could be used to solve which of the following equations? 5 x = 30 x + 3 = 7 ( x + 2) ( x - 2)

irinina [24]

Answer:

5x=30

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone please help me!!

grandymaker [24]

Answer:

rotation 90° CW about the origin we defined

Step-by-step explanation:

The image has the same orientation (clockwise order of vertices) as the pre-image, so an even number of reflections is involved. These cannot be reflections across the x- or y-axes. The longest edge has an east-west orientation in the pre-image and a south-north orientation in the image. Any reflections must have a net effect of a rotation 90° CW.

Equivalently, the image is rotated 90° clockwise from the pre-image.

With a suitable choice of center of rotation, the image can be obtained with a single 90° CW rotation transformation.

If we define the lower left corner of the pre-image as having coordinates (-1, 2), then a 90° CW rotation about (0, 0) will yield the image.

3 0

3 years ago

6.849 to the nearest hundredth

diamong [38]

Answer:

6.85

Step-by-step explanation:

5 0

3 years ago

Help me Plss Thank You ❤️​

Help me Plss Thank You ❤️