Answer:
Solution given:
Centre(h,k)=(-5,-9)
radius (r)=7
we have
Equation of a circle is;
(x-h)²+(y-k)²=r²
Substituting value;
(x+5)²+(y+9)²=7²
<u>(x+5)²+(y-9)²=49 is a required equation of a circle</u>.
Answer:
Step-by-step explanation:
We are to show that 
<u>Proof:</u>
From trigonometry identity;
From trigonometry, 2sinAcosA = Sin2A
Also note that sin(B-C) = sinBcosC - cosBsinC
sin420cos140 - cos420sin140 = sin(420-140)
The resulting equation becomes;
= 
The answer is C
4(3-x)+6x=3x+12-x All real numbers are solutions.
24x^2 +25x - 47 53
----------------------- = -8x -3 - ---------------
ax-2 ax-2
add 53/ax-2 to each side
24x^2 +25x - 47+53
----------------------- = -8x -3
ax-2
24x^2 +25x +6
----------------------- = -8x -3
ax-2
multiply each side by ax-2
24x^2 +25x +6 = (ax-2) (-8x-3)
multiply out the right hand side
24x^2 +25x +6 = -8ax^2 +16x-3ax +6
24 = -8a 25 = 16 -3a
a = -3 9 = -3a
a = -3
Choice B
Answer:
x>7
Step-by-step explanation:
x-3>4
Add 3 to both sides
x>7
Hope it helped!
