Answer:
B. $275,000
Explanation:
The second machine will be depreciate over time as it can later be used for operational purposes or another research projects. The first, as can only be used for a research project It should be considered expenses for the entire amount regardless of the useful life.
Machine B useful life 10 years
depreciation expense: cost / useful life
250,000 / 10 = 25,000
machine A 250,000 + 25,000 depreciation for machine B = 275,000 total
<span>A. It helps you to balance your risk across different types of investments</span>
Answer:
1. False. The peak of 86 MILLION occurred in the year of 1996 and not in 2001 as per the reports of food and agricultural organisation of UN.
2. True. The given statement is correct from the source.
3. False. As per the research conducted on the basis of catch reconstruction, the catches have been declining due top several reasons.
4. The last statement is totally correct as verified by the source mentioned.
Answer:D
Explanation:
The movement of protein in the plasma membrane allows for cellular adaptation to the extracellular environment
Answer:
$50.74 million
Explanation:
Interest rate per annum = 8%
Number of years = 17
Number of compounding per annum = 1
Interest rate per period (r) = 8%/1 = 8%
Number of period (n) =17 * 1 = 17
Growth rate (g) = 5%
First payment (P) = 4 ($'million)
PV of the new Chip = p/(r-g) * [1 - [(1+g)/(1+r)]^n]
PV of the new Chip = 4/(8%-5%) * [1 - [(1+5%)/(1+8%)]^17]
PV of the new Chip = 4/0.03 * [1 - [1.05/1.08]^17]
PV of the new Chip = 4/0.03 * [1 - 0.972222^17]
PV of the new Chip = 133.333 * (1 - 0.6194589804)
PV of the new Chip = 133.333 * 0.3805410196
PV of the new Chip = 50.7386757663268
PV of the new Chip = $50.74 million
