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3 years ago

All of the following statements about flexible spending accounts (FSAs) are TRUE, EXCEPT:

Business

1 answer:

Alexxandr [17]3 years ago

5 0

Answer:

c. Funds remaining in the account at the end of the year roll forward to the next year.

Explanation:

Flexible spending accounts is created by an employer for the employee and is a type of savings account that allows the account holder with certain tax benefits. The employee is required to contribute some amount from his earnings to the account. Contributions made to this account are deducted from your account thereby decreasing your taxable income.The funds are utilized for payment of qualified expenses.

The funds should be used by the end of the year. But the employer can give grace period of two and half months within which you should completely use the fund and finish it. Sometimes the employer might let you roll over $500 per year from the unused fund from your account.

So funds remaining in the FSA at the end of the year doesn't roll forward to the next year. All other statements are correct.

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2 years ago

Below are the account balances for Cowboy Law Firm at the end of December.

drek231 [11]

Answer:

<u>Cowboy Law Firm</u>

<u>Income statement for the year ended December.</u>

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Less Expenses :

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3 years ago

April runs a small shop where she provides a service. She is able to process an average of 11 customers per hour. An average of

professor190 [17]

Answer:

5. Po= 0.36

6. Pn = 0.04

7. 0.16

8. 1.11

9. 1.75

10. 9.9

Explanation:

5. Computation for the probability that April will not be working with a customer

Using this formula

Po=1-(Average number of arrival per hour/Average number of customer served per hour)

Let plug in the formula

Po= 1-(7/11 )

Po=1-0.64

Po= 0.36

Therefore the probability that April will not be working with a customer will be 0.36

6. Calculation for the probability of 5 customers in the system

Using this formula

Pn= (Average number of arrival per hour/Average number of customer served per hour)* Po

Let plug in the formula

Pn= (7/11)^5* 0.36

Pn=0.104358*0.36

Pn=0.037

Pn = 0.04 (Approximately)

Therefore the probability of 5 customers in the system will be 0.04

7. Calculation for the average time a customer spends waiting in line

Time spend Waiting in line=7^2/11(11 – 7) /7

Time spend Waiting in line=(49/44)/7

Time spend Waiting in line = 1.11/7

Time spend Waiting in line= 0.16

Therefore the average time a customer spends waiting in line will be 0.16

8. Calculation for the average number of customers waiting in line

Customers waiting in line = 7^2/11(11 – 7)

Customers waiting in line=49/44

Customers waiting in line= 1.11

Therefore the average number of customers waiting in line will be 1.11

9. Calculation for the average number of customers in the system

Average customers in the system= 1.11 +(7/11)

Average customers in the system= 1.11 +0.64

Average customers in the system = 1.75

Therefore the average number of customers in the system will be 1.75

10. Calculation for the arrival rate in order for April to stay that busy

Arrival rate = 0.9 * 11

Arrival rate = 9.9

Therefore the arrival rate in order for April to stay that busy will be 9.9

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