Answer:
C
Step-by-step explanation:
x - 7 > -6
x > -6 + 7
x > 1
• We change the inequality sign if we multiply or divide a negative number from both sides. But since it’s positive and we added it we won’t change the inequality sign.
Area for circle is πr² so πr² =28.26 and we can sub 3.14 as pi
3.14*r²=28.26 we can divide by 3.14 to get r² on it's own
r²=28.26/3.14
then we root both sides to get r on it's own
28.26/3.14=9 √9=3
and the diameter is double the radius 3*2=6 so the diameter is 6
Answer:
Colin has <em>8 sheets </em>left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = ![x](https://tex.z-dn.net/?f=x)
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:
![\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20pieces%20of%20papers%20used%20for%201st%20class%20%3D%7D%20%5Cdfrac%7Bx%7D%7B2%7D%20-5%20......%20%281%29)
Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.
![\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20pieces%20of%20papers%20used%20for%202nd%20class%20%3D%7D%20%5Cdfrac%7Bx%7D%7B2%7D%20-5%2B2%20%3D%20%5Cdfrac%7Bx%7D2%20-3%20......%20%282%29)
Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class
![\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8](https://tex.z-dn.net/?f=%5Ctext%7Bnumber%20of%20pieces%20of%20papers%20left%20for%20the%20third%20class%20%3D%20%7Dx-%28%5Cdfrac%7Bx%7D%7B2%7D-5%29-%28%5Cdfrac%7Bx%7D%7B2%7D-3%29%5C%5C%5CRightarrow%20x-%5Cdfrac%7Bx%7D2-%5Cdfrac%7Bx%7D2%2B5%2B3%5C%5C%5CRightarrow%20x-x%2B5%2B3%5C%5C%5CRightarrow%208)
So, the answer is:
Colin has <em>8</em> <em>sheets </em>left for his third class.
Answer:
27
Step-by-step explanation:
104-77=27