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FrozenT [24]
4 years ago
5

Use substitution to solve each system of equations Y=2x-2 Y=x+2

Mathematics
1 answer:
Alik [6]4 years ago
8 0
Y = 2x - 2 ⇒ 2x - y = 2  ⇒ 2x - y = 2
y = x + 2  ⇒ x - y = -2   ⇒ <u>2x - 2y = -4</u>
                                                 <u>3y</u> = <u>6</u> 
                                                  3     3
                                                   y = 2
                                            2x - 6 = 2
                                            <u>      +6   +6</u>
                                                 <u>2x</u> = <u>8</u>
                                                  2     2
                                                   x = 4
                                             (x, y) = (4, 2)

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my question is 2x^2+13x+6=0 HOW???? there are no numbers that multiply to 6 and can add to 13. Please help I'm so confused!!!
kondor19780726 [428]
Look

2x^2+13x+6
factored into
(ax+b)(cx+d)
we need to find a,b,c,d such that when multipied we get 2x^2+13x+6
first
we know that the first number hast to be 2
(2x+somethin)(1x+sometin)
and the end numbers have to multiply to 6
if we try 1 and 6
(2x+1)(x+6)=
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2x^2+13x+6
correct

so
2x^2+13x+6=0=(2x+1)(x+6)

therefor assume
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minus 1
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divide 2
x=-1/2

other one
x+6=0
mnus 6
x=-6

x=-6 or -1/2


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