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3 years ago

Use substitution to solve each system of equations Y=2x-2 Y=x+2

1 answer:

8 0

Y = 2x - 2 ⇒ 2x - y = 2 ⇒ 2x - y = 2
y = x + 2 ⇒ x - y = -2 ⇒ 2x - 2y = -4
 3y = 6
 3 3
 y = 2
 2x - 6 = 2
 +6 +6
 2x = 8
 2 2
 x = 4
 (x, y) = (4, 2)

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Which comparison is correct? 7 -7 -9 > 4 -6 > -5

ArbitrLikvidat [17]

Answer:

7 > -7

Step-by-step explanation:

-9 is not greater than -4

-6 is not greater than -5

I am not sure what 7 -7 means in your first option but if it is consistent, then yes, 7 is greater than -7.

8 0

3 years ago

Given: <SPT = <RQT, ST = RT Prove: PR = QS

andrey2020 [161]

Answer:

See explanation

Step-by-step explanation:

Consider triangles PTS and QTR. In these triangles,

$ST=RT$ - given;
$\angle SPT=\angle RQT$ - given;
$\angle STP=\angle RTQ$ - as vertical angles when lines PR and SQ intersect.

Thus, $\triangle PTS\cong \triangle QTR$ by AAS postulate.

Congruent triangles have congruent corresponding sides, so

$PT=QT$

Consider segments PR and QS:

$PR=PT+TR\ [\text{Segment addition postulate}]\\ \\QS=QT+TS\ [\text{Segment addition postulate}]\\ \\PT=QT\ [\text{Proven}]\\ \\ST=RT\ [\text{Given}]$

So,

$PR=SQ\ [\text{Substitution property}]$

7 0

3 years ago

5-3x =-10 what is x?

Delvig [45]

Answer:

x = 5

Please tell me if im incorrect and hope this helped ^^

3 0

3 years ago

Read 2 more answers

Rhonda bought a new laptop for $800. The laptop depreciates, or loses, 20% of its value each year. The value of the laptop at a

zhuklara [117]

As per the problem,

Rhonda bought a new laptop for $800.

The laptop depreciates, or loses, 20% of its value each year.

The value of the laptop at a later time can be found using the formula

$A=P(1-r)^t.....(1)$

Here we have

P=$800

r=20%=0.20

t=2 years

Substitute the values in equation (1) we get

$A=800(1-0.2)^2\\ \\ \Rightarrow A=800(0.8)^2\\ \\ \Rightarrow A=800*0.64\\ \\ \Rightarrow A=512\\$

The laptop be worth in two years will be $512.

6 0

3 years ago

Determine whether the statement is true or false. If f and g are positive increasing functions on an interval I, then fg is incr

Leno4ka [110]

Answer: false

Step-by-step explanation:

If f and g are increasing on I, this implies that f' > 0 on I and g' > 0 on I. That is both f' and g' have a positive slope. However,

Using product rule;

(fg)' = fd(g) + gd(f)

(fg)' = f * g' + f' * g

and although it is given that g' and f' are both positive we don't have any information about the sign of the values of the functions themselves(f and g). Therefore, if at least one of the functions has negative values there is the possibility that the derivative of the product will be negative. For example;

f = x, g = 5x on I = (-5, -2)

f' = 1 and g' =5 both greater than 0

f and g are both lines with positive slopes therefore they are increasing, but f * g = 5x^2 is decreasing on I.

6 0

3 years ago