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Yuki888 [10]
3 years ago
7

Armando is baking 36 batches of brownies for the bake sale. Each batch of brownies takes 1 1/15 cups of flour. What is a reasona

ble estimate of the amount of flour that he will need to bake all thirty-six batches of brownies?
A. 18
B. 36
C. 39
D. 72
Mathematics
2 answers:
8090 [49]3 years ago
8 0

Answer:

It would be 36

Step-by-step explanation:

Tomtit [17]3 years ago
3 0

Answer:

36.

Step-by-step explanation:

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Please answer this . It’s of class 8 Thank you
Katen [24]

Answer:

= (3/5)-³

= (5/3)³

= (5/3) × (5/3) × (5/3)

= (125/27)

Hope it helps.

3 0
3 years ago
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A river flows at the rate of 12 feet per minute. What is the rate in second per foot?
ASHA 777 [7]
Answer: 1/5 or 0.2 in decimal form.

Explanation:

There are 60 seconds in a minute. We know the river flows 12 ft per 1 minute. So in order to find the rate per seconds, divide: 60/12. You get the answer: 1/5 or 0.2 in decimal form.
4 0
2 years ago
PLS I need help, this is due today. thank u.
mariarad [96]
Here, you would complete it with the Pythagorean Theorem.

So, A^2 + B^2 = C^2

So 14^2 + B^2 = 14^2

This equals = B = 11.49
6 0
3 years ago
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Alice bought of a pound of grapes and ate of a pound. How many pounds were left?
vivado [14]
None. She ate the pound she bought.
7 0
3 years ago
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In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
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