Question

What would be the inverse function of g(x)=1/x-1 ? Thanks in advance.

Answer 1

Exchanging x and y and isolating y, it is found that the inverse function is:

$g^{-1}(x) = \frac{1 + x}{x}$

The function given is:

$g(x) = y = \frac{1}{x - 1}$

To find the inverse function, we exchange x and y and isolate y, hence:

$x = \frac{1}{y - 1}$

$x(y - 1) = 1$

$xy - x = 1$

$xy = 1 + x$

$y = \frac{1 + x}{x}$

Hence, the inverse function is:

$g^{-1}(x) = \frac{1 + x}{x}$

You can learn more about inverse functions at brainly.com/question/16485117