All categories

2 years ago

3 of 8 The area of a circle is 16.71cm2. Find the length of the radius rounded to 2 DP.

Mathematics

1 answer:

Cerrena [4.2K]2 years ago

6 0

Answer:

Radius = 2.31 cm

Step-by-step explanation:

Area of circle = 16.71 square centimeters

$\pi r^2 = 16.71 \\3.14r^2=16.71\\r^2=\frac{16.71}{3.14}\\r^2=5.32\\\sqrt{r^2}=\sqrt{5.32}\\r=2.306$

Radius of circle = 2.31 centimeter

You might be interested in

What is the slope of the line that passes through the points (3, 8) and (12, 1)? A. -9/7 B. -7/9 C. 7/9 D. 9/7

nekit [7.7K]

The answer to this problem is B.

4 0

2 years ago

Read 2 more answers

What is the truncation error for S4?

solong [7]

Answer:

Its B

Step-by-step explanation:

I calculated it using the formula and got B

3 0

2 years ago

1/3 + 1/2 + 1 2/3 - 4/5

mash [69]

17/10
or 1 7/10
i did it on my calculator lol

3 0

3 years ago

Seven times a number decreased by three-fourths of the same number is 25. What is the number?

Tomtit [17]

Answer:

103/28

Step-by-step explanation:

Let the number be 'x'

Equation:-

7x - 3/4 = 25

7x = 25 + 3/4

7x = 100/4 + 3/4

7x = 103/4

x = 103/(4 x 7)

x = 103/28

5 0

2 years ago

Read 2 more answers

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago