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kaheart [24]
2 years ago
9

Find the area of the rectangle ​

Mathematics
2 answers:
Zolol [24]2 years ago
4 0
6/7(W) multiplied by 1(L) gives you
6/7 yd ²
tia_tia [17]2 years ago
3 0

Answer:

\frac{6}{7} yd^{2}

Step-by-step explanation:

Area is the width (6/7 yd) multiplied by the height (1 yd).

6/7 x 1 = 6/7 yd^{2}

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Triangle ABC is rotated 45° counterclockwise about vertex A to obtain triangle XYZ. If the m∠ABC is equal to 30°, what is the m∠
prohojiy [21]

Answer:

B,30

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
The three shapes below represent the bases of three different prisms. Each grid is 1 unit x 1 unit, and each prism has a height
8_murik_8 [283]
Then it’s 20 units I think
8 0
3 years ago
Glven the line segment RT, with endpolnt R(6,9) and<br> midpoint A(-3,7)
Rzqust [24]
It would be (-12, 5)
7 0
3 years ago
ANSWER TO BE NAMED BRAINLIEST, GET A THANK YOU , BE FRIEND REQUESTED ,
Dominik [7]

1500 i did the test

4 0
3 years ago
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