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egoroff_w [7]
3 years ago
6

Which sets of three numbers could represent the lengths of the sides of a right triangle? 12, 15, 21

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

Look at the pictures! :)

HOPE THIS HELPED! HAVE A GREAT DAY! :)

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The width-to-height ratio of a certain computer monitor
Mnenie [13.5K]
<h2>24 inches</h2>

Step-by-step explanation:

It is given that \frac{\textbf{width of computer monitor}}{\textbf{height of computer monitor}}=\frac{16}{9}

It is given that \text{height of computer monitor}=13.5

\text{width of computer monitor} =\text{height of computer monitor}\times \frac{16}{9}

\text{width of computer monitor}=13.5\times \frac{16}{9} =\frac{216}{9} =24

Hence the required width in inches is 24.

5 0
3 years ago
What is 5 2<br><img src="https://tex.z-dn.net/?f=%20%5Ctimes%20" id="TexFormula1" title=" \times " alt=" \times " align="absmidd
Feliz [49]
The answer is 5×2 =10
8 0
3 years ago
Identify the median and IQR of the data set below.20222426283032Your answerWhich dota
Dennis_Churaev [7]

We are given a boxplot that contains some data. We will use the information below to analyze the given question.

STEP 1: Median

From the image above, we can see that the median represents the line drawn inside the box

This gives;

\text{Median}=24

STEP 2: Interquartile range

The interquartile range is the difference between the third quartile and the first quartile.

\begin{gathered} q_3=28 \\ q_1=22 \\ \text{IQR}=28-22 \\ \text{IQR}=6 \end{gathered}

4 0
1 year ago
Assume that when Human Resource managers are randomly selected, 62% say job applicants should follow up within two weeks. If 25
Alenkinab [10]

Using the binomial distribution, it is found that there is a 38% probability that exactly 18 of them say job applicants should follow up within two weeks.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consists of n independent Bernoulli trials.

Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

The probability that out of n trials, there'd be x successes is given by

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

Binomial probability distribution  

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

The parameters are:

n is the number of trials.

x is the number of successes.

p is the probability of success on a single trial.

In this problem:

62% say job applicants should follow up within two weeks, p = 0.62

25 managers are selected, n = 25

The probability that exactly 18 of them say job applicants should follow up within two weeks is P ( X = 18)

P( X > 18) = 1 -  ( X = 18)

= 1 - 0.62

= 0.38

38 % probability that exactly 18 of them say job applicants should follow up within two weeks.

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

8 0
2 years ago
i have 537 cookies and i need to divide them into 12 equal groups. how many cookies are in each group
katrin [286]
If you divide 537 in to 12 groups. each group would have 44 cookies and you would have 9 left.
5 0
3 years ago
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