Question

Solve by using Vertical Velocity model: h=-16t^2+vt+s

Answer 1

An equation that models the height of the ball as a function of time t is; h(t) = -16t² + 40t + 3. The maximum height that the ball will reach is 28 ft

How to Solve the Vertical velocity model?

We are given the equation for the vertical velocity model as;

h = -16t² + vt + s

Where;

v = velocity

s = starting height

h = ending height

t = time

A) From the question, we have;

v = 40 ft/s

s = 3 ft

Thus, the equation is;

h = -16t² + 40t + 3

B) To find the time that the ball reaches its maximum height, we will equate the height equation to zero and find the roots. Thus;

-16t² + 40t + 3 = 0

Using an online quadratic equation calculator gives;

t = 2.573 s

C) The maximum height that the ball will reach is;

h'(t) = -32t + 40

At h'(t) = 0;

-32t + 40 = 0

32t = 40

Thus;

t = 1.25 s

Max height = -16(1.25)² + 40(1.25) + 3

Max height = 28 ft

D) The height of the ball after 2 seconds is;

h(2) = -16(2)² + 40(2) + 3

h(2) = 19 ft

E) Time for the ball to hit the ground is;

T = 2 * 2.573

T = 5.146 s

Read more about Vertical Velocity Model at; brainly.com/question/27526920

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