blue marbles
y = yellow marbles
Sum = b+y
The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * y / (b+y-1) = 0.37
This can be solve easily by using a theorem of Bayes
0.37/0.55 = .67 or 67%
9.81 or 98.1 pretty sure it's the first one
By <span>Pythagorean triple
a²+b²=c²,
c should be longest side
10²+14²=26²
100+196=676
296</span>≠676
so sides do not form Pythagorean triple, it is not a right triangle
Answer:
neither
Step-by-step explanation:
The second and 3rd one can be modeled by by y = 100/x but the first one and the fourth one do not follow that, so the answer is neither. The first and fourth are y = 80/x
Put the values in and you will see the equations for yourself.
One
y = 80/2
y = 40
The 80 came from looking at this as an indirect variation. y = k/x
y = 40
x = 2
y = k/x
40 = k/2 Multiply both sides by 2
40 * 2 = k
k = 80
Two
y = k/x
20 = k/5
k = 20 * 5
k = 100
Answer:
Distance cover by Alyson = 16 miles
Step-by-step explanation:
Given:
Distance cover together = 39 miles
Assume;
Distance cover by Jeff = a
Distance cover by Alyson = a - 7
Find:
Distance cover by Alyson
Computation:
a + (a - 7) = 39
2a - 7 = 39
2a = 46
a = 23
Distance cover by Alyson = a - 7
Distance cover by Alyson = 23 - 7
Distance cover by Alyson = 16 miles
