Answer:
See explanation
Explanation:
From left to right, the oxides across period 3;
i) Period 3 oxides all appear white in colour. They are all crystalline solids and their melting points decrease from left to right.
ii) The volatility of period 3 oxides increases from left to right across the periodic table
iii) The metallic oxides on the right hand side adopt giant ionic structures. Silicon oxide which is in the middle of the period forms a giant covalent structure. Oxides of other elements towards the right hand side form molecular oxide structures.
iv) The acidity of oxides of period 3 increases from left to right. Metals on the left hand side form basic oxides while non-metals on the right hand side form acidic oxides. The oxide of aluminium in the middle is amphoteric.
v) The oxides of period 3 elements do not conduct electricity. However, the metallic oxides on the lefthand side conduct electricity in molten state. The non-metallic oxides on the right hand side are molecular hence they do not conduct electricity under any circumstance.
Answer:
- <u><em>50% of the offspring will have green pods.</em></u>
Explanation:
Use a upper case to identify the dominant allele and lower case to identify recessive allele.
<em>A homozygous pea plant</em> would be YY or gg. The <em>homozygous recessive pea pleant</em> would be gg (YY is dominant).
<em>A heterozygous pea plant</em> would be Yg (or gY which is the same).
The <em>Punnett Square </em>for the cross between a <em>homozygous recessive pea plant</em> (gg) and a <em>heterozygous pea plant</em> (Yg) would be:
g g
Y Yg Yg
g gg gg
Hence, <em>the offspring will have</em> two Yg, which would be yellow pods, and two gg which would be green pods.
That is, 50% of the offspring will have yellow pods and 50% will have green pods.
<h3>a) <u>Answer;</u></h3>
A- 7.30 M
<h3><u>Explanation;</u></h3>
3.65 Sodium sulfate
Na2(SO4) dissociates to give sodium ions and sulfate ions.
Na2(SO4) → 2Na+ + SO₄²₋
Therefore, twice the concentration of sodium ions as far as molarity is concerned.
<em><u>Concentration of sodium ions = 3.65 × 2= 7.3 M</u></em>
<h3>b) <u> Answer;</u></h3>
B- 2.76 M
<h3><u>Explanation;</u></h3>
b) 1.38 M sodium carbonate
Sodium carbonate dissociates completely to yield Sodium ions and carbonate ions
Na₂CO₃ → 2Na+ + CO₃²₋
The concentration of sodium ions will be twice the concentration of initial compound since it has a ratio of two.
<em>Concentration of sodium ions = 1.38 ×2 </em>
<em> = 2.76 M</em>
<h3>
c) <u>
Answer;</u></h3>
<em>0.785 M</em>
<h3><u>
Explanation;</u></h3>
b) 0.785 sodium bicarbonate
Sodium bicarbonate dissociates completely to sodium ions and a bicarbonate ions.
NaHCO₃ →Na+ + HCO₃⁻
In this case the concentration of Na+ will be equal to the concentration of the original compound since they share the same ratio.
Thus; <em><u>Na+ concentration = 0.785 M</u></em>
Answer: Electrons
Explanation: The electrons are found outside the nucleus and orbit it.
Answer:
D
Explanation:
It depend on your parents genes. What they have, is what you'll have.
~<em>Jack Pullman</em>
p.s. Mark for brainiest!
