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balu736 [363]
3 years ago
7

Pre-Lab Assignment

Chemistry
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

See explanation

Explanation:

From left to right, the oxides across period 3;

i) Period 3 oxides all appear white in colour. They are all crystalline solids and their melting points decrease from left to right.

ii) The volatility of period 3 oxides increases from left to right across the periodic table

iii) The metallic oxides on the right hand side adopt giant ionic structures. Silicon oxide which is in the middle of the period forms a giant covalent structure. Oxides of other elements towards the right hand side form molecular oxide structures.

iv) The acidity of oxides of period 3 increases from left to right. Metals on the left hand side form basic oxides while non-metals on the right hand side form acidic oxides. The oxide of aluminium in the middle is amphoteric.

v) The oxides of period 3 elements do not conduct electricity. However, the metallic oxides on the lefthand side conduct electricity in molten state. The non-metallic oxides on the right hand side are molecular hence they do not conduct electricity under any circumstance.

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If I have 17 liters of gas at 67C and 88.89 atm, what will be the pressure of the gas if I raise the temperature to 94C and decr
dmitriy555 [2]

Answer:

The correct answer is A. 140 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin:

0 ° C = 273K, 67 ° C = 273 + 67 = 340K; 94 ° C = 273 + 94 = 367K

P1xV1 /T1= P2x V2/T2

P2= ((P1xV1 /T1)xT2)/V2

P2=((88,89atm x 17L/340K)x367K)/12L= <em>135,927625 atm</em>

7 0
3 years ago
How many lobes does a single sp3 hybrid orbital have?
dangina [55]

Two lobes.

The shape of four sp3 hybrid orbitals is part s and part p-each has two lobes but one lobe is much bigger (which is the lobe used for bonding)

8 0
3 years ago
The double replacement reaction between calcium nitrate (Ca(NO​3​)​2)​ and potassium oxide (K​2O​ ) is shown below:
Llana [10]

Answer:

Mass = 2.355 g

Explanation:

Given data:

Mass of K₂O needed = ?

Mass of KNO₃ produced = 5.00 g

Solution:

Chemical equation:

K₂O + Ca(NO₃)₂     →   CaO +  2KNO₃

Number of moles of KNO₃:

Number of moles = mass/molar mass

Number of moles = 5.00 g/ 101.1 g/mol

Number of moles = 0.05 mol

now we will compare the moles of KNO₃ and K₂O.

               KNO₃           :             K₂O

                  2                :               1

                 0.05           :           1/2×0.05 = 0.025 mol

Mass of potassium oxide needed in gram:

Mass =  number of moles × molar mass

Mass = 0.025 mol × 94.2 g/mol

Mass = 2.355 g

8 0
2 years ago
Physical or chemical property sugar turns black when heated.
horrorfan [7]
From my understanding the correct answer would be phyical
8 0
3 years ago
Mn(OH)2(s) + MnO4(aq) → MnO42–(aq) (basic solution) When the equation is balanced with smallest whole number coefficients, what
PilotLPTM [1.2K]

Answer:

Hi, the given equation has some missing parts. Actual equation is- 'Mn(OH)_{2}(s)+MnO_{4}^{-}(aq.)\rightarrow MnO_{4}^{2-}(aq.)'

balanced equation: Mn(OH)_{2}(s)+4MnO_{4}^{-}(aq.)+6OH^{-}(aq.)\rightarrow 5MnO_{4}^{2-}(aq.)+4H_{2}O(l)

Explanation:

Mn(OH)_{2}(s)\rightarrow MnO_{4}^{2-}(aq.)

Balance O and H in basic medium: Mn(OH)_{2}(s)+6OH^{-}(aq.)\rightarrow MnO_{4}^{2-}(aq.)+4H_{2}O(l)

Balance charge: Mn(OH)_{2}(s)+6OH^{-}(aq.)-4e^{-}\rightarrow MnO_{4}^{2-}(aq.)+4H_{2}O(l) ........(1)

MnO_{4}^{-}(aq.)\rightarrow MnO_{4}^{2-}(aq.)

Balance charge: MnO_{4}^{-}(aq.)+e^{-}\rightarrow MnO_{4}^{2-}(aq.) .....(2)

[equation(2)\times 4]+[equation (1)]:

Mn(OH)_{2}(s)+4MnO_{4}^{-}(aq.)+6OH^{-}(aq.)\rightarrow 5MnO_{4}^{2-}(aq.)+4H_{2}O(l)

OH^{-}(aq.) is present on the left hand side of balanced equation and it's coefficient is 6

6 0
3 years ago
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