Answer:
A. Increasing the temperature will favor forward reaction and more CaCo3 formed.
B. More CaCo3 will be formed.
C. CaCo3 will decrease and more react ants formed.
D. Less CaCo3 will be formed.
E. Iridium is a catalyst so there is no effect
Explanation:
A. Temperature will increase because it's an endothermic reaction.
B. Adding Cao will favor forward reaction and more CaCo3 formed.
C. Removing methane, more react ants are formed and CaCo3 decreases.
D. Irridi is a catalyst so it has no effect on the CaCo3 but only speeds its rate of reaction.
Explanation:
Standardization is the process of creating protocols to guide the creation of a good or service based on the consensus of all the relevant parties in the industry. ... Standardization also helps in ensuring the safety, interoperability, and compatibility of goods produced.
Answer:
Pb3O4 + 4H2 → 3Pb + 4H2O
Explanation:
Pb3O4
Tritium - H2
Molar Mass of H2 Bond Polarity H-3 Hydrogen-3 3H T
Products
Lead - Pb
Molar Mass of Pb Plumbum Element 82 Bulk Lead
Water - H2O
Molar Mass of H2O Oxidation Numbers of H2O Dihydrogen Monoxide Dihydridooxygen Hoh Hydrogen Hydroxide Dihydrogen Oxide Oxidane Hydrogen Oxide Pure Water
I believe the answer to your question would be Fluorine. I hope I answered your question, my friend. :)
Answer:
The new volume is 5.92 L, which is approximately 6 L
Explanation:
As the gas temperature increases, the molecules move faster and take less time to reach the walls of the container. This means that the number of crashes per unit of time will be greater. That is, there will be an increase (for an instant) in the pressure inside the container and the volume will increase.
So Charles's Law is one of the gas laws that relates the volume and temperature of a certain amount of gas at constant pressure and says that:
- If the temperature increases the volume increases
- If the temperature decreases the volume decreases
Mathematically this is expressed by:
When you want to study two different states, an initial and a final one of a gas, this law is expressed by:
In this case:
- V1: 8 L
- T1: 473 K
- V2: ?
- T2: 350 K
Replacing:
Solving:
V2=5.92 L
<u><em>The new volume is 5.92 L, which is approximately 6 L</em></u>
