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Igoryamba
2 years ago
5

Monty Ricker obtained a used car loan of $6,000.00 at 8% for 36 months. The monthly payment is $ 187.80. The balance of the loan

after 12 payments is $ 4,159.90. The balance after the 34th payment is $ 380.60.
Mathematics
2 answers:
igomit [66]2 years ago
5 0

Answer:

What is the intrest for the 13th payment?

wel2 years ago
4 0

Answer:  What is the interset

Step-by-step explanation:

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Whoever gets it right can have brainliest, but answer ASAP!
Scilla [17]

Answer:

Hi!~I~am~beinggreat78,~and~I~will~help~you!

Let's start by breaking down the problem.

This is how it should look. ↓

60 ÷ 20 ⇒ + 3 ⇒ x * 5^2

What does that <em>x</em> mean? <em>x</em> is just a substituted value for the first 2 equations.

Now, we can solve.

60 ÷ 20 = 3

Add 3

3 + 3 = 6

Now, multiply 6 times 5 squared. What does 5 squared mean? 5 squared is just 5 times itself once. You most likely want to solve 5 squared before multiplying.

5^2~or~5 * 5 = 25

And now for the last step, multiply 25 times 6

25 * 6 = 150

With that information, the problem is solved! Your answer is 150

6 0
2 years ago
Read 2 more answers
Write a proportion for 48 aintains for $24 then how many can you buy with $4?
V125BC [204]

Step-by-step explanation:

the answer is on the pic above

7 0
2 years ago
What are the solutions to the equation
igor_vitrenko [27]

Answer:

the answer to the question is 26.0

6 0
2 years ago
What is a whole number between the square root of 27 and the square root of 39
Vinvika [58]
That number would be 6.
Since 5^2 = 25 and 6^2 = 36, we can see that the only possible whole number between sqrt(27) and sqrt(39) has to be 6.


8 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
2 years ago
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