Answer:
Seven
Step-by-step explanation:
Let G7, G8, and G9 be the numbers of students in the respective grades.
Then, G7 + G8 + G9 = LCM of G8 and G9
<em>Data:
</em>
G8 = 5
G9 = 3
<em>Calculations:
</em>
<em>Multiples of 5</em>: 1 2 10 15
<em>Multiples of 3</em>: 1 3 6 9 15
The <em>LCM</em> of 5 and 3 is 15.
G7 + 5 + 3 = 15 Combine like terms
G7 + 8 = 15 Subtract 8 from each side
G7 = 7
There are seven students in Grade 7.
Answer:
Step-by-step explanation:
We have been given an equation 
. We are asked to find the solutions of our given equation.
We will use splitting the middle term method to solve quadratic equation.
We will split middle term of our given equation into parts such that whose product is 
and whose sum is 3.
We know that such two numbers are 
.
Using zero product property, we will get:
Therefore, the solutions for our given equation are .
Answer:
13x + 7 + 4x + 15 = 90
17x + 22 = 90
17x = 68
x = 4
4(4) + 15= 16 + 15= 31
13(4) + 7 = 52 + 7 = 59
Step-by-step explanation:
Answer:
Subtract 2 from both sides.
Step-by-step explanation:
Remember to do the opposite of PEMDAS. PEMDAS is the order of operation, and stands for:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
> Also, note the equal sign, what you do to one side, you do to the other side of the equation.
First step is to subtract 2 from both sides of the equation:
3x + 2 (-2) = 29 (-2)
3x = 29 - 2
3x = 27
The second step is to divide 3 from both sides of the equation:
(3x)/3 = (27)/3
x = 27/3
x = 9
~
Answer:
Answer:
17 seedlings
Step-by-step explanation:
Given;
The seedlings are at an equal distance in a straight line.
Distance between 3rd seedling and 5th seedling = 9/10 m
So, distance between 3rd seedling and 4th seedling = 9/10 ÷ 2 = 9/20 m
So, the distance between two seedlings in a line = 9/20 m
The given distance between 2nd seedling and the last seedling = 6 3/4 m = 27/4 m
