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vlabodo [156]
3 years ago
8

What is the approximate area of the shaded region in the figure below?

Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

Answer:

  (a)  10.0 m²

Step-by-step explanation:

The radius of the inner circle is (2 m -1.1 m) = 0.9 m. The area of each circle is given by the formula ...

  A = πr²

so, the difference in areas is ...

  shaded = π(2 m)² -π(0.9 m)² = π(4 -0.81) m²

  shaded area ≈ 10.0 m²

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The smallest positive solution of tan bx = 2 is x = 0.3. Determine the general solution of tan bx = 2.
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The general solution of tan(b·x) = 2, given that the smallest positive solution is x = 0.3, is presented as follows;

\mathbf{ x =0.3 +  \dfrac{n \cdot \pi}{b}}

The given smallest positive solution of tan (b·x) = 2 is x = 0.3

The general solution of tan (b·x + c) = m, is given as follows;

\mathbf{x = \dfrac{\alpha  - c}{b}  + n \cdot \dfrac{\pi}{b}}

α = arctan(m) = x₀

The minimum positive value of the general solution is therefore presented as follows;

x_{min \ positive} = \dfrac{\alpha  - c}{b}  + 0 \times \dfrac{\pi}{b} = \dfrac{\alpha  - c}{b}

\mathbf{x_{min \ positive} = \dfrac{\alpha  - c}{b}}

In the given function, tan (b·x), we therefore, have;

c = 0, m = 2,  \dfrac{\alpha  - c}{b} = 0.3

The general solution of tan(b·x) = 2, is therefore;

\mathbf{x =0.3 +  \dfrac{n \cdot \pi}{b}}

Learn more about the general solution of a sine function here:

https://brainly.in/question/1549935

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