Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
Answer:
(d) f(x) = (x − 3)^2(x − 2)(x − 1)
Step-by-step explanation:
In this context, a crossing of the axis at x=p means there is a factor of (x-p). A "touch" of the axis at x=q means there is a factor of (x -q)^2.
A crossing at x=1 and x=2, and a touch at x=3 means the factors are ...
f(x) = (x -1)(x -2)(x -3)^2 . . . . . matches the last choice
Since this point is located in the fourth quadrant you have to rotate it 270 degrees counterclockwise which would end up being in third quadrant. which means the new point would be (-6,-9)
The answer is 1.25 meters.
hope it helps
can you choose mine as the brainliest answer
