Question

2. Find the equation of the perpendicular bisector of line PQ where the co-ordinates of P and Q are P (-2, 8) and Q (4,7)

Answer 1

Answer:

2y - 12x = 3

Step-by-step explanation:

gradient of line PQ= (7-8)/ 4+2

-1/6

gradient of perpendicular bisector of line PQ=

-1 ÷ -1/6

-1× -6

6

coordinates of the midpoint of line PQ

(-2+4)/2, (8+7)/2

(1, 15/2)

the perpendicular bisector passes through the midpoint of line PQ

Equation of the perpendicular bisector

y - 15/2 = 6(x - 1)

multiply through by 2

2y - 15 = 12(x - 1)

2y - 15 = 12x - 12

2y - 12x = 3