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aleksklad [387]

3 years ago

14

The length of a rectangle is 2 inches more than its width. The perimeter of the rectangle is 24 inches. The equation 2x + 2(x +

2) = 24, where x is the width in inches, represents this situation. The value of x from the set {1, 3, 5, 7} that holds true for the equation is . So, the width of the rectangle is inches and its length is inches.

1 answer:

Ulleksa [173]3 years ago

8 0

Answer:

Width is 5 and length is 7

Step-by-step explanation:

You can solve the equation using the distributive property and inverse operations.

2x +2(x+2)=24

2x + 2x + 4 = 24

4x + 4 = 24

4x = 20

X = 5

This means the width is 5 and the length is 7.

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3 years ago

Stephanie has 60 tickets to the carnival.She used 3/4 of her 60 tickets to play games.Then she used 1/5 of her remaining tickets

Lera25 [3.4K]

Answer:

<h2>She gave her brother 6 tickets</h2>

Step-by-step explanation:

This problem is on fractional numbers.

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1.She used 3/4 of her tickets to play game

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3 0

4 years ago

Fernando followed two diagonal paths, Paths 1 and 2, to get from his house, F, to a neighborhood corner store, C, as shown below

aleksandrvk [35]

Answer:

42 meters

Step-by-step explanation:

Given

See attachment for complete question

Required

Calculate distance FC

FC is calculated as:

$FC = Path\ 1 + Path\ 2$

Where

$Path\ 1 = FB$

$Path\ 2 = BC$

Considering $\triangle FEB$ , we have:

$FB^2 = FE^2 + BE^2$ --- Pythagoras theorem

Where

$FE = FD - BA$

$FE = 22m - 15m$

$FE = 7m$

and

$BE = CD - CA$

$BE = 32m - 8m$

$BE = 24m$

So:

$FB^2 = FE^2 + BE^2$

$FB^2 = 7^2 +24^2$

$FB^2 = 49 +576$

$FB^2 = 625$

Take square roots of both sides

$FB = 25$

So:

$Path\ 1 = 25$

Considering $\triangle BAC$ , we have:

$BC^2 = BA^2 + AC^2$ --- Pythagoras theorem

Where:

$BA = 15$ and $AC = 8$

So, we have:

$BC^2 = 15^2 + 8^2$

$BC^2 = 225 + 64$

$BC^2 = 289$

Take square roots of both sides

$BC = 17$

So;

$Path\ 2= 17$

Recall that:

$FC = Path\ 1 + Path\ 2$

$FC = 25 + 17$

$FC = 42$

6 0

3 years ago