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Nady [450]
2 years ago
5

Tossing a coin and getting heads or tails

Mathematics
1 answer:
Luden [163]2 years ago
8 0
When tossing a coin, the event of getting head and tail are mutually exclusive events. Because the probability of getting head and tail simultaneously is 0. In a six-sided die, the events “2” and “5” are mutually exclusive events. We cannot get both events 2 and 5 at the same time when we threw one die.
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Solve each equation. Round your answers to the nearest ten-thousandth. Please show work. Part 3A​
Butoxors [25]

Answer:

19.

      log9(5x^2 + 10) - log9(10) = 1

<=> log9((5x^2 + 10)/10) = log9(9)

<=> (5x^2 + 10)/10 = 9

<=> 5x^2 + 10 = 90

<=> 5x^2 = 80

<=> x^2 = 16

<=> x = +/- (4)

20.

      log5(2x^2 + 4) + log5(3) = 2

<=> log5((2x^2 + 4) x 3) = log3(9)

<=> 6x^2 + 12 = 9

<=> 6x^2 = -3

 => No real x satisfies.  ( x^2 always larger or equal to 0)

21.

      log6(8) + log6(7 - 2x^2) = 2

<=> log6(8 x (7 - 2x^2)) = log6(36)

<=> 56 - 16x^2 = 36

<=> 16x^2 = 20

<=> x^2 = 5/4

<=> x = +/- sqrt(5/4)

Hope this helps!

:)

5 0
4 years ago
Jeffery took a drive to town at an average rate of 50mph. When he returns, he drove back at the rate of 30 mph. If he spent a to
katen-ka-za [31]

Answer:

150 + 150 = 300

Step-by-step explanation:

50x = 30y  

x + y = 8

~~~~~~~~~~~~~~~

x = 8 - y

50(8-y) = 30y

400 - 50y = 30y

400 = 80y

y = 5

x= 3

6 0
3 years ago
HELP PLEASE BOTH QUESTIONS <br> ILL MARK BRAINLIST
pychu [463]

Answer:

Sorry but all I know is number 7 is x=3 I dont know how to explain

3 0
3 years ago
What is the volume of a frustum of a right pyramid with the area of the lower base square to 100 square inches, the area of the
otez555 [7]

Answer:

1

Step-by-step explanation:

7 0
3 years ago
Please help with questions 1d and e
Aleksandr-060686 [28]

(d) \frac{75}{2}, \frac{75}{4}, \frac{75}{8}

(e) 68, 82, 96

(d) note that the terms have a common ratio ( r )

r = \frac{300}{600} = \frac{150}{300} = \frac{1}{2}

to obtain any term in the sequence, multiply the previous term by \frac{1}{2}

75 × \frac{1}{2} = \frac{75}{2}

\frac{75}{2}× \frac{1}{2} = \frac{75}{4}

\frac{75}{4} × \frac{1}{2} = \frac{75}{8}

(e) note that the terms have a common difference (d )

d = 26 - 12 = 40 - 26 = 54 - 40 = 14

to obtain any term in the sequence, add 14 to the previous term

54 + 14 = 68

68 + 14 = 82

82 + 14 = 96

3 0
3 years ago
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