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denis23 [38]
3 years ago
9

Pls help it's due today​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

x = 5

y = 8.66

Step-by-step explanation:

I hope this helps!!

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Evaluate 7-5p+3q when p=1 and q=7
KIM [24]

Answer:

23

Step-by-step explanation:

<em><u>Since it gives you the values of p and q, just plug it into the expression:</u></em>

7 - 5p + 3q

7 - 5(1) + 3(7)

7 - 5 + 21

2 + 21

23

3 0
3 years ago
Read 2 more answers
Una compañía suministra electricidad. Cobra $100 mensuales fijos más 15 centavos por kilowatt hora. En los primeros 400 kilowatt
sweet [91]

Answer:

La función resultante es una función a trozos:

C_{T}(x) = \left\{\begin{array}{cc}100+0.15\cdot x,\,0\le x \le 400\\112+0.12\cdot x,\,x> 400\\\end{array}

Step-by-step explanation:

El coste total de la electricidad suministrada (C_{T}), medida en pesos, es la suma del coste fijo (C_{F}) y el coste variable (C_{V}), medidas en pesos.

C_{T} = C_{F}+C_{V} (1)

Ahora, tenemos que el coste fijo es $ 100 mensuales, así:

C_{F} = \$ \,100 (2)

Y el coste variable considera que se cobra 15 centavos por kilowatt-hora para los primeros 400 kilowatts-hora y 12 centavos por kilowatt-hora para cada kilowatt-hora que pase de 400 kilowatts-hora en el mes:

(i) Menos o igual que 400 kilowatts-hora:

C_{V} = 0.15\cdot x (3)

Donde x es la electricidad suministrada en kilowatts-hora.

(ii) Mayor que 400 kilowatts-hora:

C_{V} = 0.15\cdot (400)+0.12\cdot (x-400)

C_{V} = 12+0.12\cdot x

La función resultante es una función a trozos:

C_{T}(x) = \left\{\begin{array}{cc}100+0.15\cdot x,\,0\le x \le 400\\112+0.12\cdot x,\,x> 400\\\end{array}

3 0
3 years ago
Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expect
lubasha [3.4K]

We want to get the expected value for the given experiment, we will see that it is equal to -1/6 points, so the correct option is "negative one-sixth"

For an experiment with events {x₁, x₂, ..., xₙ}, each one with probability {p₁, p₂, ..., pₙ}, the expected value is given by:

EV = x₁*p₁ + ... + xₙ*pₙ

Here we have two events:

  • x₁ = she gets 9 points.
  • x₂ = she loses 2 points.

Let's find the probabilities of each one of these.

She gets 9 points if the sum of the two dice is equal to 8 or 12.

Each dice has 6 outcomes.

Then a combination of two dice has a total of 6*6 = 36 outcomes.

The outcomes that add to 8 or 12 are:

dice 1   dice 2  sum

2           6            8

3           5            8

4           4            8

5          6             8

6           2            8

6           6            12

So 6 out of the 36 outcomes, then the probability of this event is:

p₁ = 6/36 = 1/6

And the other event is for all the other outcomes, so the probability is just:

p₂ = 5/6

Then the expected value is:

EV = (+ 9 points)*(1/6) + (-2 points)*(5/6)  = -1/6 points.

So the correct option is negative one-sixth.

If you want to learn more about expected value, you can read:

brainly.com/question/22097128

8 0
2 years ago
Read 2 more answers
You are in charge of monitoring the pressure of a compressed air tank in a processing plant. After repeating the pressure measur
sashaice [31]

Answer:

4.46% probability that the pressure will exceed this value.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Gaussian distribution with a mean value of 69 psi and a standard deviation of 10 psi.

Gaussian distribution = normal.

This means that \mu = 69, \sigma = 10

If it is important that the pressure stays below 86 psi, what is the probability (in percent) that the pressure will exceed this value?

As a proportion, this probability is 1 subtracted by the pvalue of Z when X = 86. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{86 - 69}{10}

Z = 1.7

Z = 1.7 has a pvalue of 0.9554

1 - 0.9554 = 0.0446

0.0446*100 = 4.46%

4.46% probability that the pressure will exceed this value.

8 0
3 years ago
Do the concepts of class​ limits, marks,​ cutpoints, and midpoints make sense for qualitative​ data? Explain your answer.
tatyana61 [14]
Class limits are the smallest and the largest data value that can go into a class.

Class marks are the midpoints of the classes. They are obtained by averaging the limits.

Cutpoints are<span> specified values used to sort continuous variables into discrete categories.

</span><span>Class Midpoint is the middle value of each data class.


For qualitative data, </span>c<span>utpoints and midpoints make​ sense, but class limits and marks do​ not, since qualitative data cannot be grouped using Limit grouping.

option D.
</span>
3 0
3 years ago
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