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choli [55]
3 years ago
8

Encuentra las dimensiones de un rectangulo cuyo perímetro es 26 mts y el área es 40m2

Mathematics
1 answer:
Alja [10]3 years ago
8 0

Answer:

Las dimensiones del rectángulo son:

lado corto: 5 cm

lado largo: 8 cm

Step-by-step explanation:

Consideraciones:

El perímetro de un rectángulo se calcula así:

p = 2(lado corto + lado largo)

El área de un rectángulo se calcula así:

a = lado largo * lado largo

Planteamiento:

26 = 2(a+b)

40 = a*b

a = lado largo

b = lado corto

Desarrollo:

de la primer ecuación del planteamiento:

26/2 = a+b

13 = a+b

13-a = b

sustituyendo este último valor en la segunda formula del planteamiento:

40 = a(13-a)

40 = 13*a + a*-a

40 = 13a - a²

-a² + 13a - 40 = 0

a = {-13±√((13²)-(4*-1*-40))} / (2*-1)

a = {-13±√(169-160)} / -2

a = {-13±√9} / -2

a = {-13±3} / -2

a₁ = {-13-3} / -2 = -16 / -2 = 8

a₂ = {-13+3{ / -2 = -10 / -2 = 5

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