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o-na [289]
3 years ago
13

Plzz answer I will give brainiest and 60 points

Mathematics
2 answers:
Tomtit [17]3 years ago
6 0

Answer:

i am struggling with that too

Step-by-step explanation:

bagirrra123 [75]3 years ago
3 0

Answer:

Step-by-step explanation:

Area = length * width

=8\frac{1}{2}*6\\\\=\frac{17}{2}*6\\\\=17*3\\\\=51

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A hot air balloon rose from a height of 100 m to 400 m in 3 minutes. What was the balloon’s rate of change?
maria [59]

Answer:

1.666666667 meter per sec^2

Step-by-step explanation:

I feel like this is physic

using acceleration formla Vf-Vi/t

so 400-100/180sec

300/180

1.666666667 meter per sec^2

Hey  im still learning tell me if you feel like im wrong OwO

7 0
3 years ago
How is 4/16 eqaul to 0.25 plaessseeee help
andreyandreev [35.5K]
Okay! 4/16= 0.25 because  16/16 = 1 and so that means 12/16 = 0.75   and 8/16 = 0.50 and 4/16 = 0.25   Hope this helped!
4 0
3 years ago
Solve for y 2x+y-3z=5
Elza [17]

Answer:

<h3>A. y=-2x+3z+25</h3>

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

<u>To solve:</u>

  • The value of y.

\Longrightarrow: \sf{\sqrt{2x+y-3z}=5}

<h3>2x+y-3z=25</h3>

<u>First, you have to subtract by 2x-3z from both sides.</u>

\Longrightarrow: \sf{2x+y-3z-\left(2x-3z\right)=25-\left(2x-3z\right)}}

<u>Solve.</u>

\Longrightarrow: \boxed{\sf{y=25-2x+3z}}}

  • <u>Therefore, the correct answer is "A. y=-2x+3z+25".</u>

I hope this helps, let me know if you have any questions.

4 0
2 years ago
Read 2 more answers
What's substitution for:<br> X=y-7<br> X+8y=2
MrRissso [65]
\left \{ {{x=y-7} \atop {x+8y=2}} \right. \\\\&#10;substitute\ x=y-7\ into \ the\ second\ equation\\\\&#10;y-7+8y=2\\\\&#10;9y-7=2\ \ \ | add\ 7\\\\&#10;9y=9\ \ \ | divide\ by\ 9\\\\&#10;y=1\\\\x=y-7=1-7=-6
4 0
3 years ago
One serving of mikes crackers has 120 calories and a mass of 30 grams . How many calories are in 10 grams of the crackers
Vikki [24]
30÷10=3
120÷3=40. As a result, there are 40 calories in 10 grams of the crackers. Hope it help!
7 0
3 years ago
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