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Lana71 [14]
2 years ago
11

Work out the area of this circle.

Mathematics
2 answers:
Over [174]2 years ago
6 0
<h2><u>Given</u> :</h2>

  • Radius of circle - 6mm

<h2><u>What To Find</u> :</h2>

  • Area of circle

<h2><u>Formula Using</u> : </h2>

Area of circle = πr²

<h2><u>Solution</u> :</h2>

Area of circle = π(6mm)²

Area of circle = 36π mm²

Hence, the area of circle is 36π mm²

exis [7]2 years ago
3 0

We know that

Area of circle = πr²

=> π × (6)²

=> π × 36

=> 36π mm²

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yan [13]

Answer:

y=-\dfrac{1}{2}(x+4)^2-1

Step-by-step explanation:

Vertex form:  y=a(x-h)^2+k  

where:

  • (h, k) is the vertex
  • a is some constant

Given:

  • vertex = (-4, -1)
  • point on parabola = (-2, -3)

Substitute given values into the formula to find a:

\implies -3=a((-2)-(-4))^2+(-1)

\implies -3=a(2)^2-1

\implies -3=4a-1

\implies -2=4a

\implies a=-\dfrac{2}{4}=-\dfrac{1}{2}

Therefore, the equation of the parabola is:

y=-\dfrac{1}{2}(x+4)^2-1

6 0
1 year ago
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zhenek [66]

Answer:

9x - 7x + 10 = 18 \\ x(9 - 7) = 18 - 10 \\ 2x = 8 \\ x =  \frac{8}{2}  \\  \\ { \boxed{ \boxed{x = 4}}}

3 0
2 years ago
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PLS HELP ASAP NEED FOR A TEST
horrorfan [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

x----> the first number

y----> the second number

we know that

\frac{x}{y}=\frac{3}{4}

so

y=\frac{4}{3}x -----> equation A

x+y=35 ----> equation B

substitute equation A in equation B

x+\frac{4}{3}x=35

\frac{3x+4x}{3}=35

\frac{7}{3}x=35    

x=35*3/7=15

y=35-15=20

4 0
2 years ago
Rewrite the definition “Perpendicular lines form right angles” as a biconditional statement using “if and only if”
vovangra [49]
Well, to write the definition of "Perpendicular lines form right angel" using "if and only if". the sentence would become :
<em>
</em><em>Two lines are perpendicular if and only if they form a right angle
</em><em>
</em><em />Hope this helps


6 0
2 years ago
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Express p as the subject of the formula<br>q= p² - r ÷ t​
Rudik [331]

Answer:

p = \sqrt{q +\frac{r}{t} }

Step-by-step explanation:

q=p^{2}- r÷ t   using BODMAS

q = p^{2} - (r/t)

q + r/t = p^{2}

p=\sqrt{q+\frac{r}{t} }

7 0
3 years ago
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