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Anna007 [38]
2 years ago
9

HELPP FIRST ANSWER IS BRAINLIEST SHOW WORK PLEASE!!!!!!!!

Mathematics
1 answer:
MrRa [10]2 years ago
8 0
B. 10

Explanation: (click attached photos to see)

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) Sasha jarred 6 liters of jam after 2 days. How many days does Sasha need to spend
AlexFokin [52]

Answer:

ok she would need to spend 6 days making 18 liters because in one day she makes 3 liters so in order

day one) 3 liters

day two) 6 liters

day three) 9 liters

day four) 12 liters

day five) 15 liters

day six) 18 liters

Step-by-step explanation:

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4 years ago
Need help pls dont troll and you don’t need to do the right side just do the equation and you don’t need to do all equation you
klio [65]

Answer:

For the first, it is 7. the second one is -7. for the third, it is -6. Now, for the forth one, it is 4.

Hope this helped!

-<em>thatLilWeeb</em>

4 0
3 years ago
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Factorise x^2 - 8/X pls help
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(x-2)(x^2 +2x +4)/x

Step-by-step explanation:

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4 0
3 years ago
A day care center charges 60$ per week for one child, plus 20$ per sibling. The equation that describes the total charge t for t
Maurinko [17]

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80$ per week if you mean only 2 siblings

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Step-by-step explanation:

8 0
3 years ago
In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from
Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

H_{0}: p=27%

H_{a}: p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

<em>a. </em>

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals \frac{180}{600}=0.3 ie 30%

<em>b.</em>

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

H_{0}: p=27%

H_{a}: p>27%

<em>c.</em>

z-score of the sample proportion assuming null hypothesis is:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of working people aged 65–69 (0.3)
  • p is the proportion assumed under null hypothesis. (0.27)
  • N is the sample size (600)

then z=\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } } = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

3 0
3 years ago
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