Question

Layla has a coin that has a 60\%60%60, percent chance of showing heads each time it is flipped. She is going to flip the coin 555 times. Let xxx represent the number of heads she gets. What is the probability that she gets more than 333 heads?.

Answer 1

The probability that she gets more than 3 heads is 0.3456.

There are only two possible outcomes for a fliped coin, either it is head, or it is tail. Since the result is independent of each other coins, the binomial distribution will be used.

Given the following parameters:  

• x is the number of successes = 5 (coin flipped 5 times)
• n is the number of trials
• p is the probability of success on a single trial = 0.6

Using the binomial distribution formula:

$P(X =x)=nC_x p^x (1-p)^{n-x}\\P(X =3) = 5C_3 \ (0.6)^3 (1-0.6)^{5-3}\\P(X =3) = 5C_3 \ (0.6)^3 (0.4)^{2}\\P(X=3)=0.3456$

Hence the probability that she gets more than 3 heads is 0.3456.

Learn more on binomial distribution here: brainly.com/question/20559010