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2 years ago

9

There are 6 friends that want the same number of oranges and there are 300 oranges how much number of oranges would they get eac

h

1 answer:

zimovet [89]2 years ago

6 0

Answer:50

Step-by-step explanation:Since there are six friends and there are 500 oranges that would be 500 divided by 6 which equals 50

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Find the missing numbers is 7 and 9 and 10 right if not what are the answers for 7 and 9 and 8 and 10 please help me ?

Black_prince [1.1K]

#8 is 10, all other answers are correct

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3 years ago

Square root of 32 x square root of 1 over 18

lisov135 [29]

<h3>Solution:</h3>

$\sqrt{32} \times \sqrt{ \frac{1}{18} } \\ = \sqrt{32} \times \frac{ \sqrt{1} }{ \sqrt{18} } \\ = \sqrt{32} \times \frac{1}{ \sqrt{18} } \\ = \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} } \\ = \frac{ \sqrt{ {2}^{2} \times {2}^{2} \times 2} }{ \sqrt{2 \times {3}^{2} } } \\ = \frac{2 \times 2 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4 \times \sqrt{2} }{3 \times \sqrt{2} } \\ = \frac{4}{3}$

<h3>Answer:</h3>

$\frac{4}{3}$

<h3>Hope it helps...</h3>

ray4918 here to help

7 0

2 years ago

Find the slope and reduce.<br> P=(-8, 3) Q=(-6, 2)<br> Slope

Lyrx [107]

Answer:

$-\frac{1}{2}$

Step-by-step explanation:

Slope/Gradient = $\frac{y1-y2}{x1-x2}$

P = (-8 , 3) (x1, y1)

Q = (-6 , 2) (x2, y2)

Slope = $\frac{3-2}{-8-(-6)}$ = $\frac{1}{-8+6}$ = $\frac{1}{-2}$ = $-\frac{1}{2}$

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1 year ago

Read 2 more answers

Explain why 6 divided by 10 = .6<br><br> Use sentences and models

Anvisha [2.4K]

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3 years ago

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After studying the diagram shown, Michael makes the following conclusions:

inn [45]

Answer:

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

Step-by-step explanation:

Given:

1. DG = 3 and the area of square DEFG is 9.

2. AG = 4 and the area of square GHIA is 16.

3. DA = 5 and the area of square ABCD is 25.

So we have,

$(DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\$

Now Add DG² and AG² we get

$(DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}$

Which is also called as Pythagoras theorem i.e

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

3 0

3 years ago