Trigonometry is the study of tree-dimensional objects true or false

Mathematics

1 answer:

Fofino [41]3 years ago

6 0

False, trigonometry is not the study of three dimensional shapes.

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Hii also wondering if anyone knows how to solve this :( thank you

Scilla [17]

Answer:

x = 7

Step-by-step explanation:

The sum of interior angles is equal to 360°

9x - 4 + 8x + 2 + 13x + 30 + 19x - 11 = 360° add like terms

49x + 17 = 360 subtract 17 from both sides

49x = 343 divide both sides by 49

x = 7

replace x with the value we found to calculate each angle.

7 0

2 years ago

Read 2 more answers

A box contains 10 book covers: 5 red, 2 blue, and 3 yellow. If a student randomly selects one book cover, what is the probabilit

IgorC [24]

The probability is 5+2/10= 7/10

8 0

3 years ago

Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\$
$=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1
$

8 0

3 years ago

On Claudia's birthday, her parents open a savings account and deposit SS. They also deposit $50 each

Pie

Wacom down straight to logo and and make sure he don’t get up

3 0

3 years ago

How is the product of 2 and -5 shown on a number line

otez555 [7]

Answer: on point -10

Step-by-step explanation:

Because 2*-5 is -10.